我在Zeppelin 0.7笔记本上使用Spark 2和Scala 2.11。我有一个可以像这样打印的框架：

dfLemma.select("text", "lemma").show(20,false)

输出如下：

+---------------------------------------------------------------------------------------------------------------------------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------------+
|text                                                                                                                       |lemma                                                                                                                                                                  |
+---------------------------------------------------------------------------------------------------------------------------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------------+
|RT @Dope_Promo: When you and your crew beat your high scores on FUGLY FROG 😍🔥 https://time.com/Sxp3Onz1w8                    |[rt, @dope_promo, :, when, you, and, you, crew, beat, you, high, score, on, FUGLY, FROG, https://time.com/sxp3onz1w8]                                                      |
|RT @axolROSE: Did yall just call Kermit the frog a lizard?  https://time.com/wDAEAEr1Ay                                        |[rt, @axolrose, :, do, yall, just, call, Kermit, the, frog, a, lizard, ?, https://time.com/wdaeaer1ay]                                                                     |

我试图使输出更好的齐柏林飞船，通过：

val printcols= dfLemma.select("text", "lemma")
println("%table " + printcols)

它给出了这样的输出：

printcols: org.apache.spark.sql.DataFrame = [text: string, lemma: array<string>]

和一个新的空白齐柏林飞艇段落，

[text: string, lemma: array]

有没有一种方法可以让这个框架显示为一个格式很好的表格？TIA！TIA！