(function(images, elements) {
    var fetchImages = function() {
        if(images.length > 0) {
            var numImages = 10;
            while(images.length > 0 && numImages-- > 0) {
                // assuming your elements are <img>
                document.getElementById(elements.shift()).src = images.shift();
                // if not you could also set the background (or backgroundImage) css property
                // document.getElementById(elements.shift()).style.background = "url(" + images.shift() + ")";
            }
            setTimeout(fetchImages, 5000);
        }
    }

    // bind to window onload
    window.onload = fetchImages;
    // if you're going to use something like jquery then do something like this instead
    //$(fetchImages);
}(['url1', 'url2', 'url3'], ['img1', 'img2', 'img3']))

我想，这种东西能达到你想问的效果。
最后一行可能会被替换为

}(<%=ImageUrls %>, <%=ImageElements %>))