我写了一段代码来描述我的问题：当点击主窗口上的一个控件时，MouseLeftButtonDown命令显示一个子窗口作为模态。当在子窗口中双击时，将触发主窗口中的MouseLeftButtonUp。如何避免这种情况没有一个标志？

主

public partial class MainWindow : Window
{
    public MainWindow()
    {
        InitializeComponent();
    }

    private void MouseLeftButtonDownCommand(object sender, MouseButtonEventArgs e)
    {
        ChildWindow childWindow = new ChildWindow();
        childWindow.Owner = this;
        childWindow.ShowDialog();
    }

    private void MouseLeftButtonUpCommand(object sender, MouseButtonEventArgs e)
    {
        MessageBox.Show("Event Propagated to main window");
    }
}

主XAML

<Grid>
    <Canvas Background="Transparent" MouseLeftButtonDown="MouseLeftButtonDownCommand" MouseLeftButtonUp="MouseLeftButtonUpCommand">
        
    </Canvas>
</Grid>

酒店MODAL WINDOWS

public partial class ChildWindow : Window
{
    public ChildWindow()
    {
        InitializeComponent();
    }

    private void LeftDoubleClickCommand(object sender, MouseButtonEventArgs e)
    {
        this.Close();
    }
}

MODAL WINDOWS XAML

<Grid>
    <ListView Margin="10" MouseDoubleClick="LeftDoubleClickCommand">
        <ListViewItem Content="Coffie"></ListViewItem>
        <ListViewItem Content="Tea"></ListViewItem>
        <ListViewItem Content="Orange Juice"></ListViewItem>
        <ListViewItem Content="Milk"></ListViewItem>
        <ListViewItem Content="Iced Tea"></ListViewItem>
        <ListViewItem Content="Mango Shake"></ListViewItem>
    </ListView>
</Grid>