我试图将Firebase添加到我的flutter项目中，但是当我在调试模式下运行它时，我得到了一个错误。
如何将Firebase SDK添加到我的项目中的说明显示，我的build.gradle文件与Google所说的应该是不同的。我已经查找了一些东西，我认为我已经向文件中添加了正确的行。
以下是将Firebase SDK添加到我的flutter项目的说明：

这是我的项目>android>app>build.gradle文件：

plugins {
    id "com.android.application"
    id "kotlin-android"
    id "dev.flutter.flutter-gradle-plugin"
    id "com.google.gms.google-servides"
}

def localProperties = new Properties()
def localPropertiesFile = rootProject.file('local.properties')
if (localPropertiesFile.exists()) {
    localPropertiesFile.withReader('UTF-8') { reader ->
        localProperties.load(reader)
    }
}

def flutterVersionCode = localProperties.getProperty('flutter.versionCode')
if (flutterVersionCode == null) {
    flutterVersionCode = '1'
}

def flutterVersionName = localProperties.getProperty('flutter.versionName')
if (flutterVersionName == null) {
    flutterVersionName = '1.0'
}

android {
    namespace "com.example.myapp"
    compileSdkVersion flutter.compileSdkVersion
    ndkVersion flutter.ndkVersion

    compileOptions {
        sourceCompatibility JavaVersion.VERSION_1_8
        targetCompatibility JavaVersion.VERSION_1_8
    }

    kotlinOptions {
        jvmTarget = '1.8'
    }

    sourceSets {
        main.java.srcDirs += 'src/main/kotlin'
    }

    defaultConfig {
        // TODO: Specify your own unique Application ID (https://developer.android.com/studio/build/application-id.html).
        applicationId "com.example.deal_diligence"
        // You can update the following values to match your application needs.
        // For more information, see: https://docs.flutter.dev/deployment/android#reviewing-the-gradle-build-configuration.
        minSdkVersion flutter.minSdkVersion
        targetSdkVersion flutter.targetSdkVersion
        versionCode flutterVersionCode.toInteger()
        versionName flutterVersionName
    }

    buildTypes {
        release {
            // TODO: Add your own signing config for the release build.
            // Signing with the debug keys for now, so `flutter run --release` works.
            signingConfig signingConfigs.debug
        }
    }
}

flutter {
    source '../..'
}

dependencies {
    implementation(platform("com.google.firebase:firebase-bom:32.3.1"))
}

下面是project>android>build.gradle中的build.gradle文件：

buildscript {
    ext.kotlin_version = '1.7.10'
    repositories {
        google()
        mavenCentral()
    }

    dependencies {
        classpath 'com.android.tools.build:gradle:7.3.0'
        classpath "org.jetbrains.kotlin:kotlin-gradle-plugin:$kotlin_version"
        classpath 'com.google.gms:google-services:4.4.0'
    }

    plugins {
        id("com.google.gms.google-services") version "4.4.0" apply false <<< ERROR HERE
    }
}

allprojects {
    repositories {
        google()
        mavenCentral()
    }
}

rootProject.buildDir = '../build'
subprojects {
    project.buildDir = "${rootProject.buildDir}/${project.name}"
}
subprojects {
    project.evaluationDependsOn(':app')
}

tasks.register("clean", Delete) {
    delete rootProject.buildDir
}

这是我得到的错误：FAILURE: Build failed with an exception.

• 其中：构建文件“C：\deal_diligence\deal_diligence\android\build.gradle”行：14
• 哪里出错了：评估根项目“android”时出现问题。

在类型为org.gradle.api.internal.initialization.DefaultScriptHandler的对象上找不到参数[build_c3pybmo0bbk86suaedh5ircie$_run_closure1$_closure4@7f9d876a]的方法插件（）。
我应该有所有的最新和最伟大的，因为我昨天创建了这个项目。如何修复此错误？谢谢