污点模式perl:通过system()运行外部程序时保留suid

ghhaqwfi  于 2023-10-24  发布在  Perl
关注(0)|答案(1)|浏览(144)

我正在尝试向一个遗留脚本添加一个功能。该脚本是suid,并使用perl -T(污点模式:man perlsec),以增加安全性。我需要添加的功能是在Python中实现的。
问题是,我无法说服perlsec保留suid权限,无论我如何清理环境和命令行。
这是令人沮丧的,因为它为其他二进制文件(如/bin/id)保留了suid。/usr/bin/perl是否有未记录的特殊情况?这似乎不太可能。
有没有人知道一种方法来实现这一点?(As-is:我们没有资源来重新构建整个系统。)

解决方案:(根据@gbacon)

# use the -p option to bash
system('/bin/bash', '-p', '-c', '/usr/bin/id -un');

# or set real user and group ids
$< = $>;
$( = $);
system('/usr/bin/python', '-c', 'import os; os.system("/usr/bin/id -un")');

这给出了预期的结果!
这是我的剧本的一个精简版,它仍然显示了我的问题。

#!/usr/bin/perl -T
## This is an SUID script: man perlsec
%ENV = ( "PATH" => "" );

##### PERLSEC HELPERS #####
sub tainted (@) {
    # Prevent errors, stringifying
    local(@_, $@, $^W) = @_;  

    #let eval catch the DIE signal
    $SIG{__DIE__}  = '';      
    my $retval = not eval { join("",@_), kill 0; 1 };
    $SIG{__DIE__}  = 'myexit';      

    return $retval
}

sub show_taint {
    foreach (@_) {
        my $arg = $_; #prevent "read-only variable" nonsense
        chomp $arg;
        if ( tainted($arg) ) {
            print "TAINT:'$arg'";
        } else {
            print "ok:'$arg'";
        }
        print ", ";
    }
    print "\n";
}

### END PERLSEC HELPERS ###

# Are we SUID ? man perlsec
my $uid = `/usr/bin/id --user` ;
chomp $uid;

my $reluser = "dt-pdrel";
my $reluid = `/usr/bin/id --user $reluser 2> /dev/null`;
chomp $reluid;

if ( $uid ne $reluid ) {
    # what ? we are not anymore SUID ? somebody must do a chmod u+s $current_script
    print STDERR "chmod 4555 $myname\n";
    exit(14);
}

# comment this line if you don't want to autoflush after every print
$| = 1;

# now, we're safe, single & SUID
# - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
# BEGIN of main code itself

print "\nENVIRON UNDER BASH:\n";
run('/bin/bash', '-c', '/bin/env');

print "\nTAINT DEMO:\n";
print "\@ARGV: ";
show_taint(@ARGV);
print "\%ENV: ";
show_taint(values %ENV);
print "`cat`: ";
show_taint(`/bin/cat /etc/host.conf`);

print "\nworks:\n";
run('/usr/bin/id', '-un');
run('/usr/bin/id -un');

print "\ndoesn't work:\n";
run('/bin/bash', '-c', '/usr/bin/id -un');
run('/bin/bash', '-c', '/bin/date >> /home/dt-pdrel/date');
run('/bin/date >> /home/dt-pdrel/date');
run('/usr/bin/python', '-c', 'import os; os.system("/usr/bin/id -un")');
run('/usr/bin/python', '-c', 'import os; os.system("/usr/bin/id -un")');

sub run {
    my @cmd = @_;
    print "\tCMD: '@cmd'\n";
    print "\tSEC: ";
    show_taint(@cmd);
    print "\tOUT: ";
    system @cmd ;
    print "\n";
}

下面是输出:

$ id -un
bukzor

$ ls -l /proj/test/test.pl
-rwsr-xr-x 1 testrel asic 1976 Jul 22 14:34 /proj/test/test.pl*

$ /proj/test/test.pl foo bar

ENVIRON UNDER BASH:
        CMD: '/bin/bash -c /bin/env'
        SEC: ok:'/bin/bash', ok:'-c', ok:'/bin/env', 
        OUT: PATH=
PWD=/proj/test2/bukzor/test_dir/
SHLVL=1
_=/bin/env

TAINT DEMO:
@ARGV: TAINT:'foo', TAINT:'bar', 
%ENV: ok:'', 
`cat`: TAINT:'order hosts,bind', 

works:
        CMD: '/usr/bin/id -un'
        SEC: ok:'/usr/bin/id', ok:'-un', 
        OUT: testrel

        CMD: '/usr/bin/id -un'
        SEC: ok:'/usr/bin/id -un', 
        OUT: testrel

doesn't work:
        CMD: '/bin/bash -c /usr/bin/id -un'
        SEC: ok:'/bin/bash', ok:'-c', ok:'/usr/bin/id -un', 
        OUT: bukzor

        CMD: '/bin/bash -c /bin/date >> /home/testrel/date'
        SEC: ok:'/bin/bash', ok:'-c', ok:'/bin/date >> /home/testrel/date', 
        OUT: /bin/bash: /home/testrel/date: Permission denied

        CMD: '/bin/date >> /home/testrel/date'
        SEC: ok:'/bin/date >> /home/testrel/date', 
        OUT: sh: /home/testrel/date: Permission denied

        CMD: '/usr/bin/python -c import os; os.system("/usr/bin/id -un")'
        SEC: ok:'/usr/bin/python', ok:'-c', ok:'import os; os.system("/usr/bin/id -un")', 
        OUT: bukzor

        CMD: '/usr/bin/python -c import os; os.system("/usr/bin/id -un")'
        SEC: ok:'/usr/bin/python', ok:'-c', ok:'import os; os.system("/usr/bin/id -un")', 
        OUT: bukzor
eh57zj3b

eh57zj3b1#

您需要将您的真实的用户ID设置为有效的(suid-ed)用户ID。您可能希望为您的真实的组ID执行相同的操作:

#! /usr/bin/perl -T

use warnings;
use strict;

$ENV{PATH} = "/bin:/usr/bin";

system "id -un";
system "/bin/bash", "-c", "id -un";

# set real user and group ids
$< = $>;
$( = $);

system "/bin/bash", "-c", "id -un";

样品运行:

$ ls -l suid.pl
-rwsr-sr-x 1 nobody nogroup 177 2010-07-22 20:33 suid.pl

$ ./suid.pl 
nobody
gbacon
nobody

您看到的是已记录的bash行为:

-p

打开特权模式。在此模式下,不处理$BASH_ENV$ENV文件,不从环境继承shell函数,并且SHELLOPTSBASHOPTSCDPATHGLOBIGNORE变量,如果它们出现在环境中,如果shell以不等于真实的用户(组)id的有效用户(组)id启动,并且未提供-p选项,将执行这些操作,并将有效用户ID设置为真实的用户ID。如果在启动时提供-p选项,则不会重置有效用户ID。关闭此选项会将有效用户和组ID设置为真实的用户和组ID。
这意味着你也可以

#! /usr/bin/perl -T

use warnings;
use strict;

$ENV{PATH} = "/bin:/usr/bin";

system "/bin/bash", "-p", "-c", "id -un";

得到

nobody

回想一下,将多个参数传递给system会绕过shell,一个参数会传递给shell,但可能不会传递给bash--看看perl -MConfig -le 'print $Config{sh}'的输出。
也许可以考虑使用use English '-no_match_vars';来保持精神正常:它将提供$GID$EGID$UID$EUID等。

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