简单的嵌入式Tomcat 10示例

qmb5sa22 于 2023-11-19 发布在其他

关注(0)|答案(2)|浏览(157)

我试图让一个简单的嵌入式tomcat 10.1.0-M11示例工作，但当我转到http://localhost:8080/aa时，我总是得到localhost refused to connect。
下面是我的代码：

import jakarta.servlet.ServletException;
import jakarta.servlet.http.HttpServlet;
import jakarta.servlet.http.HttpServletRequest;
import jakarta.servlet.http.HttpServletResponse;
import java.io.File;
import java.io.IOException;
import java.io.PrintWriter;

import org.apache.catalina.Context;
import org.apache.catalina.LifecycleException;
import org.apache.catalina.startup.Tomcat;

public class App {

    public static void main(String[] args) throws LifecycleException {
        Tomcat tomcat = new Tomcat();
        tomcat.setBaseDir("temp");
        tomcat.setPort(8080);

        String contextPath = "";
        String docBase = new File(".").getAbsolutePath();

        Context context = tomcat.addContext(contextPath, docBase);

        class SampleServlet extends HttpServlet {

            @Override
            protected void doGet(HttpServletRequest req, HttpServletResponse resp)
                    throws ServletException, IOException {
                PrintWriter writer = resp.getWriter();

                writer.println("<html><title>Welcome</title><body>");
                writer.println("<h1>Have a Great Day!</h1>");
                writer.println("</body></html>");
            }
        }

        String servletName = "SampleServlet";
        String urlPattern = "/aa";

        tomcat.addServlet(contextPath, servletName, new SampleServlet());
        context.addServletMappingDecoded(urlPattern, servletName);

        tomcat.start();
        tomcat.getServer().await();
    }
}

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不情愿 *

<dependencies>
    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>servlet-api</artifactId>
        <version>3.0-alpha-1</version>
        <scope>provided</scope>
    </dependency>
    <dependency>
        <groupId>org.apache.tomcat.embed</groupId>
        <artifactId>tomcat-embed-core</artifactId>
        <version>10.1.0-M11</version>
    </dependency>
    <dependency>
        <groupId>org.apache.tomcat.embed</groupId>
        <artifactId>tomcat-embed-jasper</artifactId>
        <version>10.1.0-M11</version>
    </dependency>
    <dependency>
        <groupId>org.apache.tomcat</groupId>
        <artifactId>tomcat-jasper</artifactId>
        <version>10.1.0-M11</version>
    </dependency>
    <dependency>
        <groupId>org.apache.tomcat</groupId>
        <artifactId>tomcat-jasper-el</artifactId>
        <version>10.1.0-M11</version>
    </dependency>
    <dependency>
        <groupId>org.apache.tomcat</groupId>
        <artifactId>tomcat-jsp-api</artifactId>
        <version>10.1.0-M11</version>
    </dependency>
</dependencies>

型

更新

我已经检查了每一个版本，我发现这个bug是在9.0.0.M4版本中引入的，从那以后就没有解决过。任何更新的版本都会使this example变得无用。

tomcat

来源：https://stackoverflow.com/questions/71383171/simple-embedded-tomcat-10-example

2条答案

按热度按时间

xriantvc1#

如this question中所述，您需要添加一个Connector，可以这样做：

...
tomcat.setPort(8080);
tomcat.getConnector();
...

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赞(0）回复(0）举报 2023-11-19

8qgya5xd2#

我已经添加了2-解决方案，你可以选择任何人，所以你的最终主要功能将如下所示：

public static void main(String[] args) throws LifecycleException {
        Tomcat tomcat = new Tomcat();
        tomcat.setBaseDir("temp");
        // Solution 1
        //tomcat.setPort(8080);
        //tomcat.getConnector();

        // Solution 2, make server listen on 2 ports
        Connector connector1 = tomcat.getConnector();
        connector1.setPort(8080);
        Connector connector2 = new Connector();
        connector2.setPort(8090);
        String contextPath = "";
        String docBase = new File(".").getAbsolutePath();

        Context context = tomcat.addContext(contextPath, docBase);

        class SampleServlet extends HttpServlet {

            @Override
            protected void doGet(HttpServletRequest req, HttpServletResponse resp)
                    throws ServletException, IOException {
                PrintWriter writer = resp.getWriter();

                writer.println("<html><title>Welcome</title><body>");
                writer.println("<h1>Have a Great Day!</h1>");
                writer.println("</body></html>");
            }
        }

        String servletName = "SampleServlet";
        String urlPattern = "/aa";

        tomcat.addServlet(contextPath, servletName, new SampleServlet());
        context.addServletMappingDecoded(urlPattern, servletName);

        tomcat.start();
        tomcat.getService().addConnector(connector1);
        tomcat.getService().addConnector(connector2);
        tomcat.getServer().await();
    }

字符串

赞(0）回复(0）举报 2023-11-19

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简单的嵌入式Tomcat 10示例

2条答案

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