根据你对解析字符串c 1888 1999 Author Name的评论，你可以考虑用第一个字符创建一个switch语句。例如：

Author cAuthor;
switch(clever_name[0]) {
    case 'c':
        Author = find_author(clever_name);
        break;
    default:
        // do something else
}

字符串
Author是一个有名字、出生年份和死亡年份的类，find_author是下面可怕的意大利面条代码。我沿着了STL的字符串构造函数，find_first_of、find_first_not_of和find_last_of返回字符串中的一个位置。

Author find_author(std::string s) {
    std::string nums("0123456789");
    std::string chars(
         "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrxtuvwxyz"
                      );
    size_t pos = s.find_first_of(nums); // find the first number
    int birth = std::atoi(
        std::string(
            s, // string to copy from
            pos, // position of first integer
            // the next line finds out how many characters we need to copy
            std::string(s.begin() + pos, s.end()).find_first_not_of(nums)
        ).c_str()
        );

    // increment pos to the next character that is not a number
    pos += std::string(s.begin() + pos, s.end()).find_first_not_of(nums);

    // then increment again to the next character that is a number
    pos += std::string(s.begin() + pos, s.end()).find_first_of(nums);

    // do the same thing again to find the next date
    int death = std::atoi(
        std::string(
            s,
            pos,
            std::string(s.begin() + pos, s.end()).find_first_not_of(nums)
        ).c_str()
        );

    // increment pos to the position of the first alphabetic character
    pos += std::string(s.begin() + pos, s.end()).find_first_of(chars);

    // do the same thing we did to find the numbers to extract the name
    std::string name =
        std::string(
            s,
            pos,
            std::string(
                   s.begin() + pos, s.end()
                        ).find_last_not_of(nums) + 1
            );
    return(Author(name, birth, death));
}

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