Laravel.如何从mergedEmployees中获取removedEmployees？

piok6c0g 于 2023-11-20 发布在其他

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$removedEmployees = $mergedEmployees->diff（$uniqueEmployees）;

这是我的代码。

$employees1 = Employee::where('employment_status', '<>', 'SEPARATED')
    ->where('client_code_1', $client->client_code)
    ->where('position', $grouping->position)
    ->where('billable_rate', $grouping->billable_rate)
    ->get();

$employees2 = Employee::where('employment_status', '<>', 'SEPARATED')
    ->where('client_code_2', $client->client_code)
    ->where('position', $grouping->position)
    ->where('billable_rate', $grouping->billable_rate)
    ->get();

$mergedEmployees = $employees1->merge($employees2);
$uniqueEmployees = $mergedEmployees->unique();
$removedEmployees = $mergedEmployees->diff($uniqueEmployees);

字符串

laravel

来源：https://stackoverflow.com/questions/77401002/laravel-how-to-get-the-removedemployees-from-mergedemployees

1条答案

按热度按时间

bxgwgixi1#

Laravel合并状态
第一个月
这里看到
所以这行$mergedEmployees = $employees1->merge($employees2);已经创建了一个唯一的数组
因此，$mergedEmployees->diff($uniqueEmployees)结果为空
你应该做的是...

$employees1 = Employee::where('employment_status', '<>', 'SEPARATED')
    ->where('client_code_1', $client->client_code)
    ->where('position', $grouping->position)
    ->where('billable_rate', $grouping->billable_rate)
    ->get()->toArray();

$employees2 = Employee::where('employment_status', '<>', 'SEPARATED')
    ->where('client_code_2', $client->client_code)
    ->where('position', $grouping->position)
    ->where('billable_rate', $grouping->billable_rate)
    ->get()->toArray();

$mergedEmployees = array_merge($employees1, $employees2);
$uniqueEmployees = array_unique($mergedEmployees,SORT_REGULAR);

$removedEmployees = collect(array_map('json_decode',array_keys(array_diff_assoc(array_flip(array_map('json_encode', $mergedEmployees)),array_flip(array_map('json_encode', $uniqueEmployees))))));

字符串
这里有一个缺点，它不会处理多个副本，如果$mergedEmployees像array（1，1，1，2），$uniqueEmployees像array（1，2），结果将是array（1）

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Laravel.如何从mergedEmployees中获取removedEmployees？

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