我是一个PHP新手，我正在用PHP slim开发一个API。
我使用Visual Studio Code作为IDE和PHP扩展。
PHP中正确安装了xplayer，并且在使用XAMPP运行时，debug可以完美地运行像这样的简单代码

<?php

$fisrt= 5;

$second= 7;

$result = sum($first, $second);

echo $result;


function sum($a, $b)
{
    $c = $a +$b;
    return $c;
}

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但我被困在调试一个苗条的项目。我用composer创建了一个项目：

composer create-project slim/slim-skeleton simpleAPI

型
然后用一个简单的

composer start
> php -S localhost:8080 -t public
[Sun Oct 31 00:01:29 2021] PHP 8.0.11 Development Server (http://localhost:8080) started

型
应用程序工作，但不停止在断点。
launch.json是用vscode自动创建的，如下所示

"version": "0.2.0",
    "configurations": [
        {
            "name": "Listen for Xdebug",
            "type": "php",
            "request": "launch",
            "port": 9003
        },
        {
            "name": "Launch currently open script",
            "type": "php",
            "request": "launch",
            "program": "${file}",
            "cwd": "${fileDirname}",
            "port": 0,
            "runtimeArgs": [
                "-dxdebug.start_with_request=yes"
            ],
            "env": {
                "XDEBUG_MODE": "debug,develop",
                "XDEBUG_CONFIG": "client_port=${port}"
            }
        },
        {
            "name": "Launch Built-in web server",
            "type": "php",
            "request": "launch",
            "runtimeArgs": [
                "-dxdebug.mode=debug",
                "-dxdebug.start_with_request=yes",
                "-S",
                "localhost:0"
            ],
            "program": "",
            "cwd": "${workspaceRoot}",
            "port": 9003,
            "serverReadyAction": {
                "pattern": "Development Server \\(http://localhost:([0-9]+)\\) started",
                "uriFormat": "http://localhost:%s",
                "action": "openExternally"
            }
        }
    ]

型
vscode：1.16.2 composer：2.1.9 php：8.0.11 slim：4.7操作系统：windows 10