为什么

soup = BeautifulSoup(response.content, 'html.parser')

字符串
返回

<ul><li><li><li></li></li></li></ul>

型
而不是

<ul><li></li><li></li><li></li></ul>

型
完整代码

from datetime import datetime
import requests
from bs4 import BeautifulSoup
def is_holiday_or_weekend():
    current_year = datetime.now().year
    today = datetime.now().strftime('%Y-%m-%d')
    url = f"https://www.kalendorius.today/nedarbo-dienos/{current_year}"
    # Start a session to maintain cookies
    session = requests.Session()
    try:
        # Send initial request to get PHPSESSID cookie
        session.get(url)
        headers = {
            'User-Agent': 'Mozilla/5.0',
            'Accept': 'application/json',
        }
        # Fetch the holiday data with headers and cookies
        response = session.get(url, headers=headers)
        response.raise_for_status()
        # Parse the HTML content
        soup = BeautifulSoup(response.content, 'html.parser')
        print(soup) # here is problems, wrong html structure
        # Extract <li> elements within <ul> of class 'calendar-items-list'
        holidays_elements = soup.find_all('ul', class_='calendar-items-list')
        holidays = {}
        for ul in holidays_elements:
            print(ul)
            for index, li in enumerate(ul.find_all('li')):
                date, name = li.get_text().strip().split(' - ', 1)
                if date not in holidays:  # Add this check to avoid duplicates
                    holidays[date] = name
        # Check if today is a holiday or a weekend
        if today in holidays or datetime.now().weekday() >= 5:
            return True
        return False
    except requests.RequestException as e:
        print(f"Error fetching holiday data: {e}")
        return None
# Usage
if is_holiday_or_weekend():
    print("Today is a holiday or weekend.")
else:
    print("Today is a regular working day.")

型
如何打印每个li元素？