我的网页需要刷新后，每次搜索页面。请任何帮助。我bignner为Ajax和这里是我的索引页代码。

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>
<script type="text/javascript">
  $(document).ready(function(){
    $("#live_search").keyup(function(){
      var input = $(this).val();
      //alert(input);
      if(input != ""){
        $.ajax({
          url:"livesearch.php",
          method:"POST",
          data:{input:input},
          success:function(data){
           $("#searchresult").html(data);
          }
        });
      }else{
        $("#searchresult").css("display", "none"); 
      }
    });
  });
    
</script>

字符串
这是我的PHP代码

<?php

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includes（'our/db_connect.php'）;
if（$_POST 'input']）{

$input = $_POST['input'];
$query = "SELECT * FROM parcels WHERE reference_number LIKE '{$input}'";
$result = mysqli_query($conn, $query);
if(mysqli_num_rows($result) > 0){?>
        <table class="table table-bordered table-striped mt-4">
            <thead>
                <tr>
                    <th>tracking num</th>
                    <th>sender contact</th>
                    <th>status</th>
                    <th>From</th>
                    <th>To</th>
                </tr>
            </thead>
            <tbody>
                <?php
                while($row = mysqli_fetch_assoc($result)){
                    $ref = $row['reference_number'];
                    $sender = $row['sender_name'];
                    $from = $row['from_branch_id'];
                    $to = $row['to_branch_id'];
                    ?>
                    <tr>
                        <td><?php echo $ref;?></td>
                        <td><?php echo $sender;?></td>
                        <td><?php echo $from;?></td>
                        <td><?php echo $to;?></td>
                    </tr>
                    <?php
                }

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？>

</tbody>
        </table>
    <?php 
    
}else{
    echo "No Parcel Found";
}

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}中的值？>