我可以返回一个类的所有子类的列表吗?例如:
class Mother {}class ChildFoo: Mother {}class ChildBar: Mother {}let motherSubclasses = ... // TODOprint(motherSubclasses) // should to return [ChildFoo.self, ChildBar.self]
class Mother {
}
class ChildFoo: Mother {
class ChildBar: Mother {
let motherSubclasses = ... // TODO
print(motherSubclasses) // should to return [ChildFoo.self, ChildBar.self]
字符串
pxy2qtax1#
令人惊讶的是,即使Swift类不是NSObject的子类,Swift中的所有类似乎都是从SwiftObject派生的。SwiftObject本身没有超类。首先,处理ObjC运行时函数的 Package 器结构:
NSObject
SwiftObject
import Foundationstruct ClassInfo : CustomStringConvertible, Equatable { let classObject: AnyClass let className: String init?(_ classObject: AnyClass?) { guard classObject != nil else { return nil } self.classObject = classObject! let cName = class_getName(classObject)! self.className = String(cString: cName) } var superclassInfo: ClassInfo? { let superclassObject: AnyClass? = class_getSuperclass(self.classObject) return ClassInfo(superclassObject) } var description: String { return self.className } static func ==(lhs: ClassInfo, rhs: ClassInfo) -> Bool { return lhs.className == rhs.className }}
import Foundation
struct ClassInfo : CustomStringConvertible, Equatable {
let classObject: AnyClass
let className: String
init?(_ classObject: AnyClass?) {
guard classObject != nil else { return nil }
self.classObject = classObject!
let cName = class_getName(classObject)!
self.className = String(cString: cName)
var superclassInfo: ClassInfo? {
let superclassObject: AnyClass? = class_getSuperclass(self.classObject)
return ClassInfo(superclassObject)
var description: String {
return self.className
static func ==(lhs: ClassInfo, rhs: ClassInfo) -> Bool {
return lhs.className == rhs.className
字符串以下是您可以如何使用它:
class Mother { }class ChildFoo: Mother { }class ChildBar: Mother { }class AnIrrelevantClass { }let motherClassInfo = ClassInfo(Mother.self)!var subclassList = [ClassInfo]()var count = UInt32(0)let classList = objc_copyClassList(&count)!for i in 0..<Int(count) { if let classInfo = ClassInfo(classList[i]), let superclassInfo = classInfo.superclassInfo, superclassInfo == motherClassInfo { subclassList.append(classInfo) }}print(subclassList)
class Mother { }
class ChildFoo: Mother { }
class ChildBar: Mother { }
class AnIrrelevantClass { }
let motherClassInfo = ClassInfo(Mother.self)!
var subclassList = [ClassInfo]()
var count = UInt32(0)
let classList = objc_copyClassList(&count)!
for i in 0..<Int(count) {
if let classInfo = ClassInfo(classList[i]),
let superclassInfo = classInfo.superclassInfo,
superclassInfo == motherClassInfo
{
subclassList.append(classInfo)
print(subclassList)
型这只执行一个浅层搜索,所以它不会清理孙子类,但你明白的想法。
uwopmtnx2#
Jean Le Moignan代码的优化版本
static func subclasses<T>(of theClass: T) -> [T] { var count: UInt32 = 0, result: [T] = [] let allClasses = objc_copyClassList(&count)! let classPtr = address(of: theClass) for n in 0 ..< count { let someClass: AnyClass = allClasses[Int(n)] guard let someSuperClass = class_getSuperclass(someClass), address(of: someSuperClass) == classPtr else { continue } result.append(someClass as! T) } return result }
static func subclasses<T>(of theClass: T) -> [T] {
var count: UInt32 = 0, result: [T] = []
let allClasses = objc_copyClassList(&count)!
let classPtr = address(of: theClass)
for n in 0 ..< count {
let someClass: AnyClass = allClasses[Int(n)]
guard let someSuperClass = class_getSuperclass(someClass), address(of: someSuperClass) == classPtr else { continue }
result.append(someClass as! T)
return result
个字符对于每个Type,在运行时只有一个元类示例,因此,它们上的指针是唯一的。出于某种原因,操作符===不允许用于AnyClass,但我们可以直接比较指针性能测试:
===
let start = CFAbsoluteTimeGetCurrent() let found = RuntimeUtils.subclasses(of:UIViewController.self) let diff = CFAbsoluteTimeGetCurrent() - start print("Took \(diff) seconds, \(found.count) found")
let start = CFAbsoluteTimeGetCurrent()
let found = RuntimeUtils.subclasses(of:UIViewController.self)
let diff = CFAbsoluteTimeGetCurrent() - start
print("Took \(diff) seconds, \(found.count) found")
型产出:字符串(描述:theClass):Took 1.0465459823608398 seconds, 174 found地址(of:theClass):Took 0.2642860412597656 seconds, 174 found
Took 1.0465459823608398 seconds, 174 found
Took 0.2642860412597656 seconds, 174 found
svmlkihl3#
以下是基于Code Different之前的答案的变体,但更短:
func subclasses<T>(of theClass: T) -> [T] { var count: UInt32 = 0, result: [T] = [] let allClasses = objc_copyClassList(&count)! for n in 0 ..< count { let someClass: AnyClass = allClasses[Int(n)] guard let someSuperClass = class_getSuperclass(someClass), String(describing: someSuperClass) == String(describing: theClass) else { continue } result.append(someClass as! T) } return result}
func subclasses<T>(of theClass: T) -> [T] {
guard let someSuperClass = class_getSuperclass(someClass), String(describing: someSuperClass) == String(describing: theClass) else { continue }
字符串返回类型将根据接收变量的类型,这要归功于泛型。我想把它作为AnyClass的一个扩展来写,但不幸的是Swift不允许。
sxissh064#
objc_copyClassList返回的结果不再是可验证的。这是有效的:
public func subclasses<T>(of theClass: T) -> [T] { var count: UInt32 = 0, result: [T] = [] let classList = objc_copyClassList(&count)! defer { free(UnsafeMutableRawPointer(classList)) } let classes = UnsafeBufferPointer(start: classList, count: Int(count)) let classPtr = address(of: theClass) for someClass in classes { guard let someSuperClass = class_getSuperclass(someClass), address(of: someSuperClass) == classPtr else { continue } result.append(someClass as! T) } return result}public func address(of object: Any?) -> UnsafeMutableRawPointer { return Unmanaged.passUnretained(object as AnyObject).toOpaque()}
public func subclasses<T>(of theClass: T) -> [T] {
defer { free(UnsafeMutableRawPointer(classList)) }
let classes = UnsafeBufferPointer(start: classList, count: Int(count))
for someClass in classes {
public func address(of object: Any?) -> UnsafeMutableRawPointer {
return Unmanaged.passUnretained(object as AnyObject).toOpaque()
4条答案
按热度按时间pxy2qtax1#
令人惊讶的是,即使Swift类不是
NSObject
的子类,Swift中的所有类似乎都是从SwiftObject
派生的。SwiftObject
本身没有超类。首先,处理ObjC运行时函数的 Package 器结构:
字符串
以下是您可以如何使用它:
型
这只执行一个浅层搜索,所以它不会清理孙子类,但你明白的想法。
uwopmtnx2#
Jean Le Moignan代码的优化版本
个字符
对于每个Type,在运行时只有一个元类示例,因此,它们上的指针是唯一的。出于某种原因,操作符
===
不允许用于AnyClass,但我们可以直接比较指针性能测试:
型
产出:
字符串(描述:theClass):
Took 1.0465459823608398 seconds, 174 found
地址(of:theClass):
Took 0.2642860412597656 seconds, 174 found
svmlkihl3#
以下是基于Code Different之前的答案的变体,但更短:
字符串
返回类型将根据接收变量的类型,这要归功于泛型。
我想把它作为AnyClass的一个扩展来写,但不幸的是Swift不允许。
sxissh064#
objc_copyClassList返回的结果不再是可验证的。这是有效的:
字符串