透视MySQL表并从其他表中获取遗漏的值

olmpazwi  于 2024-01-05  发布在  Mysql
关注(0)|答案(2)|浏览(189)

有两种MySQL表:

  1. table1
  2. id | time | status
  3. -----------------------
  4. 1 | 10:00 | conn |
  5. 1 | 10:01 | disconn |
  6. 2 | 10:02 | conn |
  7. 2 | 10:03 | disconn |
  8. 3 | 10:04 | conn |
  9. table2
  10. id | time |
  11. ------------
  12. 3 | 10:05 |

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如果某个标识没有断开连接时间值,则从表2中获取该值。要获得所需结果,SQL查询是什么:

  1. id | conn | disconn|
  2. --------------------
  3. 1 | 10:00| 10:01 |
  4. 2 | 10:02| 10:03 |
  5. 3 | 10:04| 10:05 |

14ifxucb

14ifxucb1#

在这种情况下,你可以使用LEFT JOINCOALESCE。下面是示例代码:

  1. SELECT
  2. t1.id,
  3. t1.time AS conn,
  4. COALESCE(t1_disconn.time, t2.time) AS disconn
  5. FROM table1 t1
  6. LEFT JOIN table1 t1_disconn ON t1.id = t1_disconn.id AND t1_disconn.status = 'disconn'
  7. LEFT JOIN table2 t2 ON t1.id = t2.id
  8. WHERE t1.status = 'conn'
  9. ORDER BY t1.id;

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下面是示例输出:


的数据
这里是fiddle link

展开查看全部
o4tp2gmn

o4tp2gmn2#

或者,您也可以使用GROUP BY而不使用self join,如下所示:

  1. SELECT
  2. T1.ID,
  3. MAX(CASE WHEN T1.STATUS = 'conn' THEN T1.TIME END) AS CONN,
  4. COALESCE(MAX(CASE WHEN T1.STATUS = 'disconn' THEN T1.TIME END), T2.TIME) AS DISCONN
  5. FROM
  6. table1 T1
  7. LEFT JOIN table2 T2 ON T1.ID = T2.ID
  8. GROUP BY T1.ID, T2.TIME
  9. ORDER BY T1.ID;

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