光环兄弟...

SELECT *
FROM your_table
WHERE search_date_1 = (SELECT MAX(search_date_1) FROM your_table)
AND search_date_2 = (SELECT MAX(search_date_2) FROM your_table)
AND search_date_3 = (SELECT MAX(search_date_3) FROM your_table)

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请测试此代码，如果正确请接受答案。

我得到的查询结果是这样的
这是我的SQL查询：

SELECT table1.jobno AS 'Job. No',  
(SELECT CONCAT(`search_date_1`, ' - ', `last_search_by_1`) FROM table1 WHERE id IN (SELECT MAX(id)  FROM table1 WHERE jobno = table1.`jobno` AND search_by_1 != '')) AS 'Search Option 1',
(SELECT CONCAT(`search_date_2`, ' - ', `search_by_2`) FROM table1 WHERE id IN (SELECT MAX(id) FROM table1 WHERE jobno = table1.`jobno` AND search_by_2 != '')) AS 'Search Option 2', 
(SELECT CONCAT(`search_date_3`, ' - ', `search_by_3`) FROM table1 WHERE id IN (SELECT MAX(id) FROM table1 WHERE jobno = table1.`jobno` AND search_by_3 != '')) AS 'Search Option 3'
FROM `table1` AS table1 
GROUP BY table1.jobno

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