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The following query returns the columns of a composite index in multiple rows.
Question: how can we write a query that returns all columns of a composite index in one row?
Example:
create table #t
(
c int,
d varchar(5),
e varchar(10)
)
create index idx_test on #t (d, e)
Running the following query on tempdb
returns two rows for the same index. I would like it to return one row under header column_names
containing the columns d and e separated by ,
such as e,d
SELECT
i.name AS index_name,
COL_NAME(ic.object_id, ic.column_id) AS column_names
FROM
sys.indexes AS i
INNER JOIN
sys.index_columns AS ic ON i.object_id = ic.object_id
AND i.index_id = ic.index_id
WHERE
i.object_id = OBJECT_ID('#t');
Output:
index_name | column_names |
---|---|
idx_test | d |
idx_test | e |
Desired output:
| index_name | column_names |
|---------------------|------------------|
| idx_test | d,e |
1条答案
按热度按时间huwehgph1#
You just need to use
STRING_AGG
in your query and group by the index name - try this code: