jquery JavaScript数组搜索和过滤器[已关闭]

yb3bgrhw 于 2024-01-07 发布在 jQuery

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我想根据关键字创建一个新数组。
如果我搜索关键字是

“居中”结果应为[“居中”]
“align”结果应为[“左对齐”，“右对齐”，“右对齐”]
“right”结果应该是[“右-右”]
“arrow”结果应为[“左-左”，“右-右”]

const myarray = [
        {
            "align-center": [
                "align",
                "center"
            ]
        },
        {
            "align-justify": [
                "align",
                "justified"
            ]
        },
        {
            "align-left": [
                "align",
                "left",
                "arrow"
            ]
        },
        {
            "align-right": [
                "align",
                "right",
                "arrow"
            ]
        }
    ]
    let results = myarray.filter(function (name) { return  *****  
});

字符串

jquery

来源：https://stackoverflow.com/questions/77609027/javascript-array-search-and-filter

2条答案

按热度按时间

h7wcgrx31#

首先使用map()获取数组中每个对象的键。然后使用filter()返回与搜索字符串匹配的对象。

let searchKey = 'left';
function search(array, searchKey) {
  return array.map(obj => Object.keys(obj)[0]).filter(key => key.includes(searchKey));
}
console.log(search(myarray, 'align-center'));
console.log(search(myarray, 'align'));
console.log(search(myarray, 'right'));

个字符

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qc6wkl3g2#

你可以创建一个表示相反关系的对象：

const myarray = [{"align-center": ["align","center"]},{"align-justify": ["align","justified"]},{"align-left": ["align","left","arrow"]},{"align-right": ["align","right","arrow"]}]
const transposed = myarray
    .flatMap(Object.entries)
    .flatMap(([key, values]) => values.map(value => [value, key]))
    .reduce((acc, [value, key]) => ((acc[value] ??= []).push(key), acc), {});
console.log(transposed);

字符串

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jquery JavaScript数组搜索和过滤器[已关闭]

2条答案

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