numpy 用python求解一个未知参数的数学表达式

bvjxkvbb 于 2024-01-08 发布在 Python

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我有个等式
x1c 0d1x的数据
我想用Python来解t。首先，我应该在这个等式中说：

<<h r ai hint T*=1000 τ =t/t*>>*

在我问这个问题之前，我在numpy中使用了符号方法：我将t解释为符号，但我得到了这个
Error :cannot convert expression to float个
我为t写的代码，我想计算h：

def h_t(h=None,t=None):
    if h==None:
        term1 = np.sum([coeav[i] / (i + 1) * (t/1000)**(i + 1) for i in range(7)])
        term2 = coeav[7] * np.log(t/1000)
        term3 = np.sum([(coeav[i] / (7 - i)) * (1/(t/1000))**(i - 7) for i in range(8, 13)])
    elif t==None:
        
        
        return ((term1+term2+term3)*1000+hint/r)*r

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numpy

来源：https://stackoverflow.com/questions/77572540/solve-a-mathematical-expression-about-a-specific-unknown-parameter-with-python

1条答案

按热度按时间

c6ubokkw1#

>>> from sympy import *
>>> coaev=[17.190126419067383, -11.550975799560547, 7.005699634552002, -2.862142
80128479, 0.7931802868843079, -0.13392554223537445, 0.010209172032773495, -8.967
597007751465, 3.3796420097351074, -0.7651314735412598 ,0.10340806096792221 ,-0.0
07709052879363298 ,0.0002440817333990708]; r= 8.31415; h=17609
>>> coeav=coaev
>>> var('hint t')
(hint, t)
>>> term1 = sum([coeav[i] / (i + 1) * (t/1000)**(i + 1) for i in range(7)])
>>> term2 = coeav[7] * log(t/1000)
>>> term3 = sum([(coeav[i] / (7 - i)) * (1/(t/1000))**(i - 7) for i in range(8,
13)])
>>> eq = ((term1+term2+term3)*1000+hint/r)*r
Look for a good guess near solution
>>> eq.subs(hint,h).subs(t,1).n()
-390126303482586.
>>> eq.subs(hint,h).subs(t,11).n()
-1616907300.09601
>>> eq.subs(hint,h).subs(t,111).n()
73731.7541309398
OK, got a sign change so guess in the middle
>>> nsolve(eq.subs(hint,h),50)  # assuming you mean hint = h
54.5730717247901

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numpy 用python求解一个未知参数的数学表达式

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