我通过以下方式从Android KMM项目中创建了一个xcframework：

#!/bin/bash

./gradlew :shared:packForXCodeArm -PXCODE_CONFIGURATION=Release
./gradlew :shared:packForXCodeX64 -PXCODE_CONFIGURATION=Release
FRAMEWORK_NAME="shared"
ARM64PATH="shared/build/xcode-framework-arm/${FRAMEWORK_NAME}.framework"
X64PATH="shared/build/xcode-framework-X64/${FRAMEWORK_NAME}.framework"
UNIVERSAL_PATH="shared/build/xcode-framework-universal/"

xcodebuild -create-xcframework -framework "${ARM64PATH}" -framework "${X64PATH}" -output "${UNIVERSAL_PATH}/${FRAMEWORK_NAME}.xcframework"

字符串
我的build.gradle.kts包含：

val packForXcodeArm by tasks.creating(Sync::class) {
    group = "build"
    val mode = System.getenv("CONFIGURATION") ?: "DEBUG"
    val framework = kotlin.targets.getByName<org.jetbrains.kotlin.gradle.plugin.mpp.KotlinNativeTarget>("iosArm64").binaries.getFramework(mode)
    inputs.property("mode", mode)
    dependsOn(framework.linkTask)
    val targetDir = File(buildDir, "xcode-framework-arm")
    from({ framework.outputDirectory })
    into(targetDir)
}

val packForXcodeX64 by tasks.creating(Sync::class) {
    group = "build"
    val mode = System.getenv("CONFIGURATION") ?: "DEBUG"
    val framework = kotlin.targets.getByName<org.jetbrains.kotlin.gradle.plugin.mpp.KotlinNativeTarget>("iosX64").binaries.getFramework(mode)
    inputs.property("mode", mode)
    dependsOn(framework.linkTask)
    val targetDir = File(buildDir, "xcode-framework-X64")
    from({ framework.outputDirectory })
    into(targetDir)
}

型
在我的M1上的Xcode中，当不使用Rosetta时，

ld: warning: ignoring file /Users/.../Library/Developer/Xcode/DerivedData/froeling_ios-dwqfcfqkcvofjtgtuipjhkedehfx/Build/Products/Debug-iphonesimulator/shared.framework/shared, building for iOS Simulator-arm64 but attempting to link with file built for iOS Simulator-x86_64
Undefined symbols for architecture arm64:
  "_OBJC_CLASS_$_SharedNetworkRequests", referenced from:
      objc-class-ref in LoginView.o

型
有没有一种方法可以在Xcode中创建一个没有Rosetta的xcframework？