当你使用pitch2D变量进行纹理操作时，底层的分配应该是一个适当的 pitched 分配。我认为通常人们会使用cudaMallocPitch来创建它。然而，要求是：
cudaResourceDesc：：res：：pitch 2D：：pitchInline以字节为单位指定两行之间的间距，并且必须与cudaDeviceProp：：texturePitchAlignment对齐。
在我的GPU上，最后一个属性是32。我不知道你的GPU，但我打赌你的GPU的属性不是4。但是你在这里指定了4：

resDesc.res.pitch2D.pitchInBytes = 4;

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同样，我认为人们通常会使用使用cudaMallocPitch创建的间距分配来实现这一点。然而，如果行到行的维度（以字节为单位）可以被texturePitchAlignment整除（在我的例子中是32），那么我确实可以传递普通的线性分配。
我做的另一个改变是使用cudaCreateChannelDesc<>()而不是像你一样手动设置参数。这会创建一组不同的desc参数，似乎也会影响结果。研究差异应该不难。
当我调整你的代码来解决这些问题时，我得到的结果对我来说似乎是合理的：

$ cat t30.cu
#include <stdio.h>
#include <stdint.h>
typedef uint8_t mt;  // use an integer type
__global__ void kernel(cudaTextureObject_t tex)
{
    int x = threadIdx.x;
    int y = threadIdx.y;
    mt val = tex2D<mt>(tex, x, y);
    printf("%d, ", val);
}
int main(int argc, char **argv)
{
    cudaDeviceProp prop;
    cudaGetDeviceProperties(&prop, 0);
    printf("texturePitchAlignment: %lu\n", prop.texturePitchAlignment);
    cudaTextureObject_t tex;
    const int num_rows = 4;
    const int num_cols = prop.texturePitchAlignment*1; // should be able to use a different multiplier here
    const int ts = num_cols*num_rows;
    const int ds = ts*sizeof(mt);
    mt dataIn[ts];
    for (int i = 0; i < ts; i++) dataIn[i] = i;
    mt* dataDev = 0;
    cudaMalloc((void**)&dataDev, ds);
    cudaMemcpy(dataDev, dataIn, ds, cudaMemcpyHostToDevice);
    struct cudaResourceDesc resDesc;
    memset(&resDesc, 0, sizeof(resDesc));
    resDesc.resType = cudaResourceTypePitch2D;
    resDesc.res.pitch2D.devPtr = dataDev;
    resDesc.res.pitch2D.width = num_cols;
    resDesc.res.pitch2D.height = num_rows;
    resDesc.res.pitch2D.desc = cudaCreateChannelDesc<mt>();
    resDesc.res.pitch2D.pitchInBytes = num_cols*sizeof(mt);
    struct cudaTextureDesc texDesc;
    memset(&texDesc, 0, sizeof(texDesc));
    cudaCreateTextureObject(&tex, &resDesc, &texDesc, NULL);
    dim3 threads(4, 4);
    kernel<<<1, threads>>>(tex);
    cudaDeviceSynchronize();
    printf("\n");
    return 0;
}
$ nvcc -o t30 t30.cu
$ cuda-memcheck ./t30
========= CUDA-MEMCHECK
texturePitchAlignment: 32
0, 1, 2, 3, 32, 33, 34, 35, 64, 65, 66, 67, 96, 97, 98, 99,
========= ERROR SUMMARY: 0 errors
$

型
正如评论中所问的，如果我要做类似的事情，但使用cudaMallocPitch和cudaMemcpy2D，它可能看起来像这样：

$ cat t1421.cu
#include <stdio.h>
#include <stdint.h>
typedef uint8_t mt;  // use an integer type
__global__ void kernel(cudaTextureObject_t tex)
{
    int x = threadIdx.x;
    int y = threadIdx.y;
    mt val = tex2D<mt>(tex, x, y);
    printf("%d, ", val);
}
int main(int argc, char **argv)
{
    cudaDeviceProp prop;
    cudaGetDeviceProperties(&prop, 0);
    printf("texturePitchAlignment: %lu\n", prop.texturePitchAlignment);
    cudaTextureObject_t tex;
    const int num_rows = 4;
    const int num_cols = prop.texturePitchAlignment*1; // should be able to use a different multiplier here
    const int ts = num_cols*num_rows;
    const int ds = ts*sizeof(mt);
    mt dataIn[ts];
    for (int i = 0; i < ts; i++) dataIn[i] = i;
    mt* dataDev = 0;
    size_t pitch;
    cudaMallocPitch((void**)&dataDev, &pitch,  num_cols*sizeof(mt), num_rows);
    cudaMemcpy2D(dataDev, pitch, dataIn, num_cols*sizeof(mt), num_cols*sizeof(mt), num_rows, cudaMemcpyHostToDevice);
    struct cudaResourceDesc resDesc;
    memset(&resDesc, 0, sizeof(resDesc));
    resDesc.resType = cudaResourceTypePitch2D;
    resDesc.res.pitch2D.devPtr = dataDev;
    resDesc.res.pitch2D.width = num_cols;
    resDesc.res.pitch2D.height = num_rows;
    resDesc.res.pitch2D.desc = cudaCreateChannelDesc<mt>();
    resDesc.res.pitch2D.pitchInBytes = pitch;
    struct cudaTextureDesc texDesc;
    memset(&texDesc, 0, sizeof(texDesc));
    cudaCreateTextureObject(&tex, &resDesc, &texDesc, NULL);
    dim3 threads(4, 4);
    kernel<<<1, threads>>>(tex);
    cudaDeviceSynchronize();
    printf("\n");
    return 0;
}
$ nvcc -o t1421 t1421.cu
$ cuda-memcheck ./t1421
========= CUDA-MEMCHECK
texturePitchAlignment: 32
0, 1, 2, 3, 32, 33, 34, 35, 64, 65, 66, 67, 96, 97, 98, 99,
========= ERROR SUMMARY: 0 errors
$

型
虽然我们这里有纹理对象，但很容易证明纹理引用也会发生类似的问题。你不能创建任意小的2D纹理引用，就像你不能创建任意小的2D纹理对象一样。我也不打算提供演示，因为它会在很大程度上重复上面的内容，人们不应该在新的开发工作中使用纹理引用-纹理对象是更好的方法。