你可以像这样使用defaultdict和extend：

from collections import defaultdict

new_dict = defaultdict(list)
for d in [dict_1, dict_2]:
    for key, value in d.items():
        new_dict[key].extend(value)

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如果您的字典具有相同的键，则可以使用Collections中的Counter

from collections import Counter

dict_1 = {"a": ["1"], "b": ["3"]}
dict_2 = {"a": ["2"], "b": ["3"]}

# Use Counter to merge the dictionaries
new_dict = Counter(dict_1)
new_dict.update(dict_2)

# Convert the Counter back to a dictionary
new_dict = dict(new_dict)

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Or/ If else编写自己的函数

dict_1 = {"a": ["1"], "b": ["3"]}
dict_2 = {"a": ["2"], "b": ["3"]}

new_dict = {}

# Iterate over the keys of both dictionaries
for key in set(dict_1.keys()) | set(dict_2.keys()):
    # Merge the lists if the key is present in both dictionaries
    new_dict[key] = dict_1.get(key, []) + dict_2.get(key, [])

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