TypeScript 将具有解构参数的函数进行转换后，参数名称会丢失,

yks3o0rb 于 8个月前发布在 TypeScript

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建议

🔍 搜索词

元组，标签，参数，解构

✅ 可实现性检查清单

我的建议满足以下准则：

[x] 这不会对现有的TypeScript/JavaScript代码造成破坏性的更改
[ x] 这不会改变现有JavaScript代码的运行时行为
[ x] 这可以在不根据表达式的类型发出不同的JS的情况下实现
[x] 这不是一个运行时特性(例如库功能，具有JavaScript输出的非ECMAScript语法，JS的新语法糖等)
[ x] 这个特性会与TypeScript's Design Goals的其他部分一致。

⭐ 建议

当使用元组类型捕获函数参数时，如果任何参数被解构，则会丢失参数名称，这会导致在尝试确定原始类型参数顺序时出现不太理想的情况。

📃 动机示例

// trivial exampled
const transform = <T, U extends unknown[]>(
   factory: (...args: U) => T
) : ((...args: U) => T) => factory
const transformed = transform(({ test } : { test: string }, b: string) : string => `${test}:`${b}`)
/* 
The intellisense for the transformed function shows args_0, args_1, the first 
argument clearly has no name, however the second does but is still not shown. If 
all arguments are named then everything works as expected.  I realize this 
is a fairly trivial example, however, it would significantly improve usage of 
transformed functions, particularly if those function have multiple primitive 
arguments whose order could be confused without names. 
Additionally I understand the potential for argument name collision, e.g. 
if argument two was for some reason called args_0, however, I believe this 
case is unlikely and also could be fixed with a numeric suffix which would 
still retain the intent.
*/