本文整理了Java中java.lang.CharSequence.chars()方法的一些代码示例，展示了CharSequence.chars()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。CharSequence.chars()方法的具体详情如下：
包路径：java.lang.CharSequence
类名称：CharSequence
方法名：chars

CharSequence.chars介绍

暂无

代码示例

代码示例来源：origin: stackoverflow.com

int streamMethod(final String data, final IntPredicate predicate) {
  if (data.chars().anyMatch(predicate)) {
    doThrow();
  }
  return data.length();
}

代码示例来源：origin: stackoverflow.com

Set<Integer> chars = new HashSet<>();
String s = /* Your lowercase string */;
s.length > 25 && s.chars()
  .filter(i -> i >= 'a' && i <= 'z') //only alphabet
  .filter(chars::add) //add to our tracking set if we reach this point
  .filter(i -> chars.size() == 26) //filter the 26th letter found
  .findAny().isPresent(); //if the 26th is found, return

代码示例来源：origin: stackoverflow.com

String str = "testString";

//[t, e, s, t, S, t, r, i, n, g]
Character[] charObjectArray = 
  str.chars().mapToObj(c -> (char)c).toArray(Character[]::new);

代码示例来源：origin: stackoverflow.com

Stream<Character> sch = "abc".chars().mapToObj(i -> (char)i);
sch.forEach(ch -> System.out.printf("%c %s%n", ch, ch.getClass().getName()));

a java.lang.Character
b java.lang.Character
c java.lang.Character

代码示例来源：origin: org.assertj/assertj-core

private boolean containsOneOrMoreWhitespaces(CharSequence actual) {
 return actual.chars().anyMatch(Character::isWhitespace);
}

代码示例来源：origin: org.assertj/assertj-core

private boolean strictlyContainsWhitespaces(CharSequence actual) {
 return actual.chars().allMatch(Character::isWhitespace);
}

代码示例来源：origin: stackoverflow.com

// avoid this at all costs
int streamParallelMethod(final String data, IntPredicate predicate) {
  if (data.chars().parallel().anyMatch(predicate)) {
    doThrow();
  }
  return data.length();
}

代码示例来源：origin: joel-costigliola/assertj-core

private boolean strictlyContainsWhitespaces(CharSequence actual) {
 return actual.chars().allMatch(Character::isWhitespace);
}

代码示例来源：origin: joel-costigliola/assertj-core

private boolean containsOneOrMoreWhitespaces(CharSequence actual) {
 return actual.chars().anyMatch(Character::isWhitespace);
}

代码示例来源：origin: stackoverflow.com

String someString = "123123";
boolean isNumeric = someString.chars().allMatch( Character::isDigit );

代码示例来源：origin: stackoverflow.com

public static long countUniqueCharacters(String input) {
  return input.chars()
      .distinct()
      .count();
}

代码示例来源：origin: stackoverflow.com

if (data.chars().anyMatch(predicate)) {
  doThrow();
if (data.chars().parallel().anyMatch(predicate)) {
  doThrow();

代码示例来源：origin: stackoverflow.com

String s = "a.b.c.d";
long result = s.chars().filter(ch -> ch == '.').count();

代码示例来源：origin: stackoverflow.com

public static void main(String[] args)
{
  int num = 1234567;  
  int[]digits = Integer.toString(num).chars().map(c -> c-='0').toArray(); 
  for(int d : digits)
    System.out.print(d);    
}

代码示例来源：origin: stackoverflow.com

public static int getNumber(String number) {
  return number.chars().reduce(0, (a, b) -> 10 * a + b - '0');
}

代码示例来源：origin: aol/cyclops

/**
 * Construct a ReactiveSeq from a String
 *
 * @param input String to construct ReactiveSeq from
 * @return ReactiveSeq from a String
 */
public static OneShotStreamX<Integer> fromCharSequence(CharSequence input){
  return Streams.<Integer>oneShotStream(input.chars().spliterator(),Optional.empty());
}

代码示例来源：origin: aol/cyclops

public static LazyString of(CharSequence seq){
  return fromLazySeq(LazySeq.fromStream( seq.chars().mapToObj(i -> (char) i)));
}

代码示例来源：origin: inferred/FreeBuilder

private void parse(CharSequence chars) {
  chars.chars().forEach(c -> parser.parse((char) c));
 }
}

代码示例来源：origin: stackoverflow.com

public static BigInteger factorialOf(int x) {
  return IntStream.rangeClosed(1, x).mapToObj(BigInteger::valueOf)
    .reduce(BigInteger::multiply).orElse(BigInteger.ONE);
}
public static int sumOf(BigInteger y) {
  return y.toString().chars().map(i -> i-'0').sum();
}

代码示例来源：origin: stackoverflow.com

public static int countWords(String s) {
  return s.chars().reduce(0, (x, y) -> {
    if((char)y == ' ')
      return x + 1;
    return x;
  });
}