本文整理了Java中java.awt.CardLayout.previous()
方法的一些代码示例,展示了CardLayout.previous()
的具体用法。这些代码示例主要来源于Github
/Stackoverflow
/Maven
等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。CardLayout.previous()
方法的具体详情如下:
包路径:java.awt.CardLayout
类名称:CardLayout
方法名:previous
[英]Flips to the previous card of the specified container. If the currently visible card is the first one, this method flips to the last card in the layout.
[中]翻转到指定容器的上一张卡。如果当前可见的卡是第一张卡,则此方法将翻转到布局中的最后一张卡。
代码示例来源:origin: stackoverflow.com
public void actionPerformed(ActionEvent e) {
CardLayout cl = (CardLayout) cards.getLayout();
cl.previous(cards);
代码示例来源:origin: IanDarwin/javasrc
public void actionPerformed(ActionEvent e) {
mgr.previous(jf.getContentPane());
}
}));
代码示例来源:origin: syedlopez/proguard
/**
* Selects the previous tab.
*/
public void previous()
{
cardLayout.previous(cardPanel);
updateButtonSelection();
}
代码示例来源:origin: net.kieker-monitoring/kieker
private void previousStep() {
this.currentStepIndex--;
this.mainPanelLayout.previous(this.mainPanel);
this.nextButton.setEnabled(true);
this.previousButton.setEnabled(this.currentStepIndex > 0);
this.saveCurrentConfiguration();
}
代码示例来源:origin: stackoverflow.com
CardLayout layout = new CardLayout();
panelCombination.setLayout(layout);
// add all panels.
....
private void PreviousMouseClicked(java.awt.event.MouseEvent evt) {
layout.previous(panelCombination);
代码示例来源:origin: kieker-monitoring/kieker
private void previousStep() {
this.currentStepIndex--;
this.mainPanelLayout.previous(this.mainPanel);
this.nextButton.setEnabled(true);
this.previousButton.setEnabled(this.currentStepIndex > 0);
this.saveCurrentConfiguration();
}
代码示例来源:origin: orbisgis/orbisgis
@Override
public void actionPerformed(ActionEvent e) {
index--;
layout.previous(mainPanel);
updateButtonsStatus();
}
});
代码示例来源:origin: sing-group/GC4S
private void showPrevioustStep() {
if(canMoveToPreviousStep()) {
this.wizardMainPanelLayout.previous(this.wizardMainPanel);
this.currentStep--;
this.stepChanged();
}
}
代码示例来源:origin: stackoverflow.com
cardlayout.previous(pageHolder);
代码示例来源:origin: robo-code/robocode
public void back() {
currentIndex--;
getWizardController().stateChanged(null);
getCardLayout().previous(this);
}
代码示例来源:origin: onyxbits/dummydroid
public void actionPerformed(ActionEvent e) {
CardLayout layout = (CardLayout) formContainer.getLayout();
if (type == FORWARD) {
try {
getCurrent().commitForm();
layout.next(formContainer);
}
catch (Exception exp) {
JOptionPane.showMessageDialog(null, exp.getMessage(), "Error", JOptionPane.ERROR_MESSAGE);
exp.printStackTrace();
return;
}
}
if (type == BACK) {
layout.previous(formContainer);
}
toScreen();
}
代码示例来源:origin: stackoverflow.com
@Override
public void actionPerformed(ActionEvent event) {
cards.previous(cardPanel);
代码示例来源:origin: edu.stanford.protege/org.coode.owlviz
/**
* Programmatically causes the Wizard to display
* the previous page. If the Wizard is already
* on the first page then nothing happens.
*/
public void prevPage()
{
currentPage--;
if(currentPage < 0)
{
currentPage = 0;
}
else
{
getPagePanelLayout().previous(pagePanel);
setButtonState();
firePageChangedEvent();
}
}
代码示例来源:origin: stackoverflow.com
switchPanels.previous(panelCombination);
代码示例来源:origin: stackoverflow.com
public void actionPerformed(ActionEvent ae) {
cl.previous(cards);
代码示例来源:origin: stackoverflow.com
public void actionPerformed(ActionEvent ae) {
cl.previous(cards);
代码示例来源:origin: stackoverflow.com
public void actionPerformed(ActionEvent e) {
CardLayout cl = (CardLayout) cards.getLayout();
cl.previous(cards);
代码示例来源:origin: stackoverflow.com
cardlayout.previous(cardHolder);
代码示例来源:origin: stackoverflow.com
layout.previous(panel);
代码示例来源:origin: stackoverflow.com
public void actionPerformed(ActionEvent evt) {
CardLayout cardLayout = (CardLayout) panelContainer.getLayout();
cardLayout.previous(panelContainer);
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