本文整理了Java中org.springframework.ldap.filter.Filter.equals()方法的一些代码示例，展示了Filter.equals()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Filter.equals()方法的具体详情如下：
包路径：org.springframework.ldap.filter.Filter
类名称：Filter
方法名：equals

Filter.equals介绍

[英]All filters must implement equals.
[中]所有过滤器都必须实现equals。

代码示例

代码示例来源：origin: org.apereo.service.persondir/person-directory-impl

@Override
public boolean equals(final Object o) {
  return this.delegateFilter.equals(o);
}

代码示例来源：origin: org.jasig.service.persondir/person-directory-impl

@Override
public boolean equals(final Object o) {
  return this.delegateFilter.equals(o);
}

代码示例来源：origin: org.springframework.ldap/spring-ldap-core

@Override
public boolean equals(Object o) {
  if (this == o) return true;
  if (o == null || getClass() != o.getClass()) return false;
  NotFilter notFilter = (NotFilter) o;
  if (filter != null ? !filter.equals(notFilter.filter) : notFilter.filter != null) return false;
  return true;
}

代码示例来源：origin: spring-projects/spring-ldap

@Override
public boolean equals(Object o) {
  if (this == o) return true;
  if (o == null || getClass() != o.getClass()) return false;
  NotFilter notFilter = (NotFilter) o;
  if (filter != null ? !filter.equals(notFilter.filter) : notFilter.filter != null) return false;
  return true;
}

代码示例来源：origin: org.apache.servicemix.bundles/org.apache.servicemix.bundles.spring-ldap

@Override
public boolean equals(Object o) {
  if (this == o) return true;
  if (o == null || getClass() != o.getClass()) return false;
  NotFilter notFilter = (NotFilter) o;
  if (filter != null ? !filter.equals(notFilter.filter) : notFilter.filter != null) return false;
  return true;
}

代码示例来源：origin: apache/servicemix-bundles

@Override
public boolean equals(Object o) {
  if (this == o) return true;
  if (o == null || getClass() != o.getClass()) return false;
  NotFilter notFilter = (NotFilter) o;
  if (filter != null ? !filter.equals(notFilter.filter) : notFilter.filter != null) return false;
  return true;
}