org.eclipse.jdt.internal.compiler.parser.Parser.asi()方法的使用及代码示例

x33g5p2x  于2022-01-26 转载在 其他  
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本文整理了Java中org.eclipse.jdt.internal.compiler.parser.Parser.asi()方法的一些代码示例，展示了Parser.asi()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Parser.asi()方法的具体详情如下：
包路径：org.eclipse.jdt.internal.compiler.parser.Parser
类名称：Parser
方法名：asi

Parser.asi介绍

暂无

代码示例

代码示例来源：origin: org.eclipse.scout.sdk.deps/org.eclipse.jdt.core

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: com.google.code.maven-play-plugin.org.eclipse.jdt/org.eclipse.jdt.core

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: org.jibx.config.3rdparty.org.eclipse/org.eclipse.jdt.core

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: org.eclipse.tycho/org.eclipse.jdt.core

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: trylimits/Eclipse-Postfix-Code-Completion

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: org.eclipse.jdt.core.compiler/ecj

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: org.eclipse.jdt/org.eclipse.jdt.core

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: org.eclipse.jetty.orbit/org.eclipse.jdt.core

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: com.vaadin/vaadin-client-compiler-deps

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: org.eclipse.scout.sdk.deps/ecj

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: com.ovea.tajin.server/tajin-server-tomcat7

  1. private int mergeCandidate(int state, int buffer_position) {
  2.   char[] name1 = this.lexStream.name(this.buffer[buffer_position]);
  3.   char[] name2 = this.lexStream.name(this.buffer[buffer_position + 1]);
  4.   int len  = name1.length + name2.length;
  5.   char[] str = CharOperation.concat(name1, name2);
  6.   for (int k = Parser.asi(state); Parser.asr[k] != 0; k++) {
  7.     int l = Parser.terminal_index[Parser.asr[k]];
  8.     if (len == Parser.name[l].length()) {
  9.       char[] name = Parser.name[l].toCharArray();
  10.       if (CharOperation.equals(str, name, false)) {
  11.         return Parser.asr[k];
  12.       }
  13.     }
  14.   }
  15.   return 0;
  16. }

代码示例来源：origin: org.eclipse.jdt.core.compiler/ecj

  1. for (i = Parser.asi(next_state); Parser.asr[i] != 0; i++) {
  2.   symbol = Parser.asr[i];
  3.   if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL) {
  4.   for (i = Parser.asi(stck[stack_top]); Parser.asr[i] != 0; i++) {
  5.     symbol = Parser.asr[i];
  6.     if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL && this.list[symbol] == 0) {

代码示例来源：origin: com.vaadin/vaadin-client-compiler-deps

  1. for (i = Parser.asi(next_state); Parser.asr[i] != 0; i++) {
  2.   symbol = Parser.asr[i];
  3.   if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL) {
  4.   for (i = Parser.asi(stck[stack_top]); Parser.asr[i] != 0; i++) {
  5.     symbol = Parser.asr[i];
  6.     if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL && this.list[symbol] == 0) {

代码示例来源：origin: com.google.code.maven-play-plugin.org.eclipse.jdt/org.eclipse.jdt.core

  1. for (i = Parser.asi(next_state); Parser.asr[i] != 0; i++) {
  2.   symbol = Parser.asr[i];
  3.   if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL) {
  4.   for (i = Parser.asi(stck[stack_top]); Parser.asr[i] != 0; i++) {
  5.     symbol = Parser.asr[i];
  6.     if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL && this.list[symbol] == 0) {

代码示例来源：origin: org.eclipse.scout.sdk.deps/ecj

  1. for (i = Parser.asi(next_state); Parser.asr[i] != 0; i++) {
  2.   symbol = Parser.asr[i];
  3.   if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL) {
  4.   for (i = Parser.asi(stck[stack_top]); Parser.asr[i] != 0; i++) {
  5.     symbol = Parser.asr[i];
  6.     if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL && this.list[symbol] == 0) {

代码示例来源：origin: trylimits/Eclipse-Postfix-Code-Completion

  1. for (i = Parser.asi(next_state); Parser.asr[i] != 0; i++) {
  2.   symbol = Parser.asr[i];
  3.   if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL) {
  4.   for (i = Parser.asi(stck[stack_top]); Parser.asr[i] != 0; i++) {
  5.     symbol = Parser.asr[i];
  6.     if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL && this.list[symbol] == 0) {

代码示例来源：origin: org.eclipse.jdt/org.eclipse.jdt.core

  1. for (i = Parser.asi(next_state); Parser.asr[i] != 0; i++) {
  2.   symbol = Parser.asr[i];
  3.   if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL) {
  4.   for (i = Parser.asi(stck[stack_top]); Parser.asr[i] != 0; i++) {
  5.     symbol = Parser.asr[i];
  6.     if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL && this.list[symbol] == 0) {

代码示例来源：origin: org.eclipse.tycho/org.eclipse.jdt.core

  1. for (i = Parser.asi(next_state); Parser.asr[i] != 0; i++) {
  2.   symbol = Parser.asr[i];
  3.   if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL) {
  4.   for (i = Parser.asi(stck[stack_top]); Parser.asr[i] != 0; i++) {
  5.     symbol = Parser.asr[i];
  6.     if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL && this.list[symbol] == 0) {

代码示例来源：origin: org.jibx.config.3rdparty.org.eclipse/org.eclipse.jdt.core

  1. for (i = Parser.asi(next_state); Parser.asr[i] != 0; i++) {
  2.   symbol = Parser.asr[i];
  3.   if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL) {
  4.   for (i = Parser.asi(stck[stack_top]); Parser.asr[i] != 0; i++) {
  5.     symbol = Parser.asr[i];
  6.     if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL && this.list[symbol] == 0) {

代码示例来源：origin: org.eclipse.jetty.orbit/org.eclipse.jdt.core

  1. for (i = Parser.asi(next_state); Parser.asr[i] != 0; i++) {
  2.   symbol = Parser.asr[i];
  3.   if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL) {
  4.   for (i = Parser.asi(stck[stack_top]); Parser.asr[i] != 0; i++) {
  5.     symbol = Parser.asr[i];
  6.     if (symbol != EOFT_SYMBOL && symbol != ERROR_SYMBOL && this.list[symbol] == 0) {

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