org.apache.jena.query.Query.hasHaving()方法的使用及代码示例

x33g5p2x  于2022-01-28 转载在 其他  
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本文整理了Java中org.apache.jena.query.Query.hasHaving方法的一些代码示例,展示了Query.hasHaving的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Query.hasHaving方法的具体详情如下:
包路径:org.apache.jena.query.Query
类名称:Query
方法名:hasHaving

Query.hasHaving介绍

暂无

代码示例

代码示例来源:origin: apache/jena

  1. @Override
  2. public void visitHaving(Query query)
  3. {
  4. if ( query.hasHaving() )
  5. x ^= query.getHavingExprs().hashCode() ;
  6. }

代码示例来源:origin: apache/jena

  1. @Override
  2. public void visitHaving(Query query) {
  3. if (query.hasHaving()) {
  4. for (Expr expr : query.getHavingExprs())
  5. newQuery.addHavingCondition(expr);
  6. }
  7. }

代码示例来源:origin: SmartDataAnalytics/jena-sparql-api

  1. @Override
  2. public void visitHaving(Query query) {
  3. if ( query.hasHaving() ) {
  4. for (Expr expr : query.getHavingExprs())
  5. newQuery.addHavingCondition(expr) ;
  6. }
  7. }

代码示例来源:origin: ch.epfl.bluebrain.nexus.org.topbraid/shacl

  1. if(result.hasHaving()) {
  2. NodeTransform nodeTransform = new NodeTransform() {
  3. @Override

代码示例来源:origin: TopQuadrant/shacl

  1. if(result.hasHaving()) {
  2. NodeTransform nodeTransform = new NodeTransform() {
  3. @Override

代码示例来源:origin: apache/jena

  1. @Override
  2. public void visitHaving(Query query)
  3. {
  4. if ( query.hasHaving() )
  5. {
  6. out.print("HAVING") ;
  7. for (Expr expr : query.getHavingExprs())
  8. {
  9. out.print(" ") ;
  10. fmtExpr.format(expr) ;
  11. }
  12. out.println() ;
  13. }
  14. }

代码示例来源:origin: apache/jena

  1. if ( query.hasHaving() )

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