java.util.Stack.elements()方法的使用及代码示例

x33g5p2x  于2022-01-29 转载在 其他  
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本文整理了Java中java.util.Stack.elements()方法的一些代码示例，展示了Stack.elements()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Stack.elements()方法的具体详情如下：
包路径：java.util.Stack
类名称：Stack
方法名：elements

Stack.elements介绍

暂无

代码示例

代码示例来源：origin: belerweb/pinyin4j

  1. public Enumeration getSteps() {
  2.  return steps_.elements();
  3. }

代码示例来源：origin: belerweb/pinyin4j

  1. /** A one-level clone in which the steps list is cloned but not the steps objects themselves.
  2.  * It is OK for different XPaths to share Steps because they are immutable. */
  3. public Object clone() {
  4.  Step[] steps = new Step[steps_.size()];
  5.  Enumeration step = steps_.elements();
  6.  for (int i = 0; i < steps.length; ++i)
  7.   steps[i] = (Step) step.nextElement();
  8.  return new XPath(absolute_, steps);
  9. }

代码示例来源：origin: belerweb/pinyin4j

  1. private String generateString() {
  2.  StringBuffer result = new StringBuffer();
  3.  boolean first = true;
  4.  for (Enumeration i = steps_.elements(); i.hasMoreElements();) {
  5.   Step step = (Step) i.nextElement();
  6.   if (!first || absolute_) {
  7.    result.append('/');
  8.    if (step.isMultiLevel()) result.append('/');
  9.   }
  10.   result.append(step.toString());
  11.   first = false;
  12.  }
  13.  return result.toString();
  14. }

代码示例来源：origin: com.belerweb/pinyin4j

  1. public Enumeration getSteps() {
  2.  return steps_.elements();
  3. }

代码示例来源：origin: info.magnolia/magnolia-rendering

  1. @Override
  2. public AreaDefinition getParentAreaDefinition() {
  3.   if (currentRenderableDefinition instanceof AreaDefinition) {
  4.     return (AreaDefinition) currentRenderableDefinition;
  5.   }
  6.   Enumeration<StackState> elements = stack.elements();
  7.   while (elements.hasMoreElements()) {
  8.     StackState state = elements.nextElement();
  9.     if (state.renderableDefinition instanceof AreaDefinition) {
  10.       return (AreaDefinition) state.renderableDefinition;
  11.     }
  12.   }
  13.   return null;
  14. }

代码示例来源：origin: open-eid/digidoc4j

  1. private boolean findTagOnStack(String tag)
  2. {
  3.   java.util.Enumeration eTags = m_tags.elements();
  4.   while(eTags.hasMoreElements()) {
  5.     String t2 = (String)eTags.nextElement();
  6.     if(t2.equals(tag))
  7.       return true;
  8.   }
  9.   return false;
  10. }

代码示例来源：origin: org.netbeans.modules/org-netbeans-modules-php-editor

  1. private String getContextClassName() {
  2.   String contextClassName = null;
  3.   Enumeration<DefinitionScope> elements = scopes.elements();
  4.   while (elements.hasMoreElements()) {
  5.     DefinitionScope nextElement = elements.nextElement();
  6.     if (nextElement.enclosingClass != null) {
  7.       contextClassName = nextElement.enclosingClass.getName();
  8.     }
  9.   }
  10.   return contextClassName;
  11. }

代码示例来源：origin: org.jboss/jboss-common-core

  1. /**
  2.  * Are we in an extension namespace?
  3.  *
  4.  * @return true if the current stack of open namespaces includes
  5.  *               an extension namespace.
  6.  */
  7. protected boolean inExtensionNamespace() {
  8.  boolean inExtension = false;
  9.  Enumeration elements = namespaceStack.elements();
  10.  while (!inExtension && elements.hasMoreElements()) {
  11.   String ns = (String) elements.nextElement();
  12.   if (ns == null) {
  13.  inExtension = true;
  14.   } else {
  15.  inExtension = (!ns.equals(tr9401NamespaceName)
  16.        && !ns.equals(namespaceName));
  17.   }
  18.  }
  19.  return inExtension;
  20. }

代码示例来源：origin: com.belerweb/pinyin4j

  1. /** A one-level clone in which the steps list is cloned but not the steps objects themselves.
  2.  * It is OK for different XPaths to share Steps because they are immutable. */
  3. public Object clone() {
  4.  Step[] steps = new Step[steps_.size()];
  5.  Enumeration step = steps_.elements();
  6.  for (int i = 0; i < steps.length; ++i)
  7.   steps[i] = (Step) step.nextElement();
  8.  return new XPath(absolute_, steps);
  9. }

代码示例来源：origin: org.netbeans.modules/org-netbeans-modules-php-editor

  1. private String getContextSuperClassName() {
  2.   String contextClassName = null;
  3.   Enumeration<DefinitionScope> elements = scopes.elements();
  4.   while (elements.hasMoreElements()) {
  5.     DefinitionScope nextElement = elements.nextElement();
  6.     if (nextElement.enclosingClass != null && nextElement.enclosingClass.superClass != null) {
  7.       contextClassName = nextElement.enclosingClass.superClass.getName();
  8.     }
  9.   }
  10.   return contextClassName;
  11. }

代码示例来源：origin: org.apache.servicemix.bundles/org.apache.servicemix.bundles.jaxp-ri

  1. /**
  2.  * Are we in an extension namespace?
  3.  *
  4.  * @return true if the current stack of open namespaces includes
  5.  *               an extension namespace.
  6.  */
  7. protected boolean inExtensionNamespace() {
  8.  boolean inExtension = false;
  9.  Enumeration elements = namespaceStack.elements();
  10.  while (!inExtension && elements.hasMoreElements()) {
  11.   String ns = (String) elements.nextElement();
  12.   if (ns == null) {
  13.  inExtension = true;
  14.   } else {
  15.  inExtension = (!ns.equals(tr9401NamespaceName)
  16.        && !ns.equals(namespaceName));
  17.   }
  18.  }
  19.  return inExtension;
  20. }

代码示例来源：origin: sun-jaxb/jaxb-xjc

  1. /**
  2.  * Are we in an extension namespace?
  3.  *
  4.  * @return true if the current stack of open namespaces includes
  5.  *               an extension namespace.
  6.  */
  7. protected boolean inExtensionNamespace() {
  8.  boolean inExtension = false;
  9.  Enumeration elements = namespaceStack.elements();
  10.  while (!inExtension && elements.hasMoreElements()) {
  11.   String ns = (String) elements.nextElement();
  12.   if (ns == null) {
  13.  inExtension = true;
  14.   } else {
  15.  inExtension = (!ns.equals(tr9401NamespaceName)
  16.        && !ns.equals(namespaceName));
  17.   }
  18.  }
  19.  return inExtension;
  20. }

代码示例来源：origin: com.sun.xml.parsers/jaxp-ri

  1. /**
  2.  * Are we in an extension namespace?
  3.  *
  4.  * @return true if the current stack of open namespaces includes
  5.  *               an extension namespace.
  6.  */
  7. protected boolean inExtensionNamespace() {
  8.  boolean inExtension = false;
  9.  Enumeration elements = namespaceStack.elements();
  10.  while (!inExtension && elements.hasMoreElements()) {
  11.   String ns = (String) elements.nextElement();
  12.   if (ns == null) {
  13.  inExtension = true;
  14.   } else {
  15.  inExtension = (!ns.equals(tr9401NamespaceName)
  16.        && !ns.equals(namespaceName));
  17.   }
  18.  }
  19.  return inExtension;
  20. }

代码示例来源：origin: com.sun.org.apache.xml.internal/resolver

  1. /**
  2.  * Are we in an extension namespace?
  3.  *
  4.  * @return true if the current stack of open namespaces includes
  5.  *               an extension namespace.
  6.  */
  7. protected boolean inExtensionNamespace() {
  8.  boolean inExtension = false;
  9.  Enumeration elements = namespaceStack.elements();
  10.  while (!inExtension && elements.hasMoreElements()) {
  11.   String ns = (String) elements.nextElement();
  12.   if (ns == null) {
  13.  inExtension = true;
  14.   } else {
  15.  inExtension = (!ns.equals(tr9401NamespaceName)
  16.        && !ns.equals(namespaceName));
  17.   }
  18.  }
  19.  return inExtension;
  20. }

代码示例来源：origin: com.tngtech.java/property-loader

  1. private void throwIfRecursionInIncludes(String fileName) {
  2.   if (fileNameStack.contains(fileName)) {
  3.     StringBuilder sb = propertyLoaderFactory.getStringBuilder();
  4.     sb.append("property file include recursion: ");
  5.     Enumeration<String> elements = fileNameStack.elements();
  6.     while (elements.hasMoreElements()) {
  7.       String currentFileName = elements.nextElement();
  8.       sb.append(currentFileName);
  9.       sb.append(" -> ");
  10.     }
  11.     sb.append(fileName);
  12.     throw new PropertyLoaderException(sb.toString());
  13.   }
  14. }

代码示例来源：origin: com.belerweb/pinyin4j

  1. private String generateString() {
  2.  StringBuffer result = new StringBuffer();
  3.  boolean first = true;
  4.  for (Enumeration i = steps_.elements(); i.hasMoreElements();) {
  5.   Step step = (Step) i.nextElement();
  6.   if (!first || absolute_) {
  7.    result.append('/');
  8.    if (step.isMultiLevel()) result.append('/');
  9.   }
  10.   result.append(step.toString());
  11.   first = false;
  12.  }
  13.  return result.toString();
  14. }

代码示例来源：origin: org.fudaa.framework.ctulu/ctulu-fu

  1. Enumeration entities = entityStack.elements();
  2. while (entities.hasMoreElements()) {
  3.  String e = (String) entities.nextElement();

代码示例来源：origin: org.apache.cocoon/cocoon-pipeline-components

  1. Enumeration enumeration = ancestors.elements();
  2. while (enumeration.hasMoreElements()) {
  3.   resolver.release((Source) enumeration.nextElement());

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