本文整理了Java中com.google.android.exoplayer2.Timeline.getPreviousWindowIndex()方法的一些代码示例，展示了Timeline.getPreviousWindowIndex()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Timeline.getPreviousWindowIndex()方法的具体详情如下：
包路径：com.google.android.exoplayer2.Timeline
类名称：Timeline
方法名：getPreviousWindowIndex

Timeline.getPreviousWindowIndex介绍

[英]Returns the index of the window before the window at index windowIndex depending on the repeatMode and whether shuffling is enabled.
[中]根据repeatMode和是否启用混洗，在index windowIndex处返回窗口之前的窗口索引。

代码示例

代码示例来源：origin: google/ExoPlayer

@Override
public int getPreviousWindowIndex(int windowIndex, @Player.RepeatMode int repeatMode,
  boolean shuffleModeEnabled) {
 return timeline.getPreviousWindowIndex(windowIndex, repeatMode, shuffleModeEnabled);
}

代码示例来源：origin: google/ExoPlayer

@Override
public int getPreviousWindowIndex(int windowIndex, @Player.RepeatMode int repeatMode,
  boolean shuffleModeEnabled) {
 int childPreviousWindowIndex = timeline.getPreviousWindowIndex(windowIndex, repeatMode,
   shuffleModeEnabled);
 return childPreviousWindowIndex == C.INDEX_UNSET ? getLastWindowIndex(shuffleModeEnabled)
   : childPreviousWindowIndex;
}

代码示例来源：origin: google/ExoPlayer

/**
 * Asserts that previous window indices for each window depending on the repeat mode and the
 * shuffle mode are equal to the given sequence.
 */
public static void assertPreviousWindowIndices(
  Timeline timeline,
  @Player.RepeatMode int repeatMode,
  boolean shuffleModeEnabled,
  int... expectedPreviousWindowIndices) {
 for (int i = 0; i < timeline.getWindowCount(); i++) {
  assertThat(timeline.getPreviousWindowIndex(i, repeatMode, shuffleModeEnabled))
    .isEqualTo(expectedPreviousWindowIndices[i]);
 }
}

代码示例来源：origin: google/ExoPlayer

/**
 * Asserts that previous window indices for each window depending on the repeat mode and the
 * shuffle mode are equal to the given sequence.
 */
public static void assertPreviousWindowIndices(
  Timeline timeline,
  @Player.RepeatMode int repeatMode,
  boolean shuffleModeEnabled,
  int... expectedPreviousWindowIndices) {
 for (int i = 0; i < timeline.getWindowCount(); i++) {
  assertThat(timeline.getPreviousWindowIndex(i, repeatMode, shuffleModeEnabled))
    .isEqualTo(expectedPreviousWindowIndices[i]);
 }
}

代码示例来源：origin: google/ExoPlayer

@Override
public final int getPreviousWindowIndex() {
 Timeline timeline = getCurrentTimeline();
 return timeline.isEmpty()
   ? C.INDEX_UNSET
   : timeline.getPreviousWindowIndex(
     getCurrentWindowIndex(), getRepeatModeForNavigation(), getShuffleModeEnabled());
}

代码示例来源：origin: google/ExoPlayer

int previousWindowIndexInChild = getTimelineByChildIndex(childIndex).getPreviousWindowIndex(
  windowIndex - firstWindowIndexInChild,
  repeatMode == Player.REPEAT_MODE_ALL ? Player.REPEAT_MODE_OFF : repeatMode,

代码示例来源：origin: ChangWeiBa/AesExoPlayer

/**
   * 上一首
   */
  private void previous() {
    Timeline timeline = player.getCurrentTimeline();
    if (timeline.isEmpty()) {
      return;
    }
    int windowIndex = player.getCurrentWindowIndex();
    timeline.getWindow(windowIndex, window);
    int previousWindowIndex = timeline.getPreviousWindowIndex(windowIndex, player.getRepeatMode());
    Timber.e("previousWindowIndex:" + previousWindowIndex);
    Timber.e("getCurrentPosition:" + player.getCurrentPosition());
    Timber.e("isDynamic:" + window.isDynamic);
    Timber.e("isSeekable:" + window.isSeekable);
    Timber.e("TIME_UNSET:" + C.TIME_UNSET);
    Timber.e("TIME_UNSET:" + C.TIME_UNSET);
    if (previousWindowIndex != C.INDEX_UNSET) {
      player.seekTo(previousWindowIndex, C.TIME_UNSET);
    } else {
      Timber.e("seekTo（0）:");
      Timber.e("已经是第一首");
//            player.seekTo(0);
    }
  }