com.linecorp.centraldogma.internal.Util.isValidNumericChar()方法的使用及代码示例

x33g5p2x  于2022-02-01 转载在 其他  
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本文整理了Java中com.linecorp.centraldogma.internal.Util.isValidNumericChar()方法的一些代码示例,展示了Util.isValidNumericChar()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Util.isValidNumericChar()方法的具体详情如下:
包路径:com.linecorp.centraldogma.internal.Util
类名称:Util
方法名:isValidNumericChar

Util.isValidNumericChar介绍

暂无

代码示例

代码示例来源:origin: line/centraldogma

  1. private static boolean isValidIpV4Word(CharSequence word, int from, int toExclusive) {
  2. final int len = toExclusive - from;
  3. final char c0;
  4. final char c1;
  5. final char c2;
  6. if (len < 1 || len > 3 || (c0 = word.charAt(from)) < '0') {
  7. return false;
  8. }
  9. if (len == 3) {
  10. return (c1 = word.charAt(from + 1)) >= '0' &&
  11. (c2 = word.charAt(from + 2)) >= '0' &&
  12. (c0 <= '1' && c1 <= '9' && c2 <= '9' ||
  13. c0 == '2' && c1 <= '5' && (c2 <= '5' || c1 < '5' && c2 <= '9'));
  14. }
  15. return c0 <= '9' && (len == 1 || isValidNumericChar(word.charAt(from + 1)));
  16. }

代码示例来源:origin: com.linecorp.centraldogma/centraldogma-common-shaded

  1. private static boolean isValidIpV4Word(CharSequence word, int from, int toExclusive) {
  2. final int len = toExclusive - from;
  3. final char c0;
  4. final char c1;
  5. final char c2;
  6. if (len < 1 || len > 3 || (c0 = word.charAt(from)) < '0') {
  7. return false;
  8. }
  9. if (len == 3) {
  10. return (c1 = word.charAt(from + 1)) >= '0' &&
  11. (c2 = word.charAt(from + 2)) >= '0' &&
  12. (c0 <= '1' && c1 <= '9' && c2 <= '9' ||
  13. c0 == '2' && c1 <= '5' && (c2 <= '5' || c1 < '5' && c2 <= '9'));
  14. }
  15. return c0 <= '9' && (len == 1 || isValidNumericChar(word.charAt(from + 1)));
  16. }

代码示例来源:origin: com.linecorp.centraldogma/centraldogma-common

  1. private static boolean isValidIpV4Word(CharSequence word, int from, int toExclusive) {
  2. final int len = toExclusive - from;
  3. final char c0;
  4. final char c1;
  5. final char c2;
  6. if (len < 1 || len > 3 || (c0 = word.charAt(from)) < '0') {
  7. return false;
  8. }
  9. if (len == 3) {
  10. return (c1 = word.charAt(from + 1)) >= '0' &&
  11. (c2 = word.charAt(from + 2)) >= '0' &&
  12. (c0 <= '1' && c1 <= '9' && c2 <= '9' ||
  13. c0 == '2' && c1 <= '5' && (c2 <= '5' || c1 < '5' && c2 <= '9'));
  14. }
  15. return c0 <= '9' && (len == 1 || isValidNumericChar(word.charAt(from + 1)));
  16. }

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