org.apache.felix.resolver.Util.isMultiple()方法的使用及代码示例

x33g5p2x  于2022-02-01 转载在 其他  
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本文整理了Java中org.apache.felix.resolver.Util.isMultiple()方法的一些代码示例，展示了Util.isMultiple()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Util.isMultiple()方法的具体详情如下：
包路径：org.apache.felix.resolver.Util
类名称：Util
方法名：isMultiple

Util.isMultiple介绍

暂无

代码示例

代码示例来源：origin: apache/felix

  1. private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
  2. {
  3.   // Sanity check for multiple.
  4.   if (Util.isMultiple(req))
  5.   {
  6.     return false;
  7.   }
  8.   // If we've already permutated this requirement in another
  9.   // uses constraint, don't permutate it again just continue
  10.   // with the next uses constraint.
  11.   if (mutated.contains(req))
  12.   {
  13.     return true;
  14.   }
  15.   // See if we can permutate the candidates for blamed
  16.   // requirement; there may be no candidates if the resource
  17.   // associated with the requirement is already resolved.
  18.   if (permutation.canRemoveCandidate(req))
  19.   {
  20.     permutation.removeFirstCandidate(req);
  21.     mutated.add(req);
  22.     return true;
  23.   }
  24.   return false;
  25. }

代码示例来源：origin: at.bestsolution.efxclipse.eclipse/org.eclipse.osgi

  1. public void permutate(Requirement req, List<Candidates> permutations)
  2. {
  3.   if (!Util.isMultiple(req) && canRemoveCandidate(req))
  4.   {
  5.     Candidates perm = copy();
  6.     perm.removeFirstCandidate(req);
  7.     permutations.add(perm);
  8.   }
  9. }

代码示例来源：origin: forge/roaster

  1. private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
  2. {
  3.   // Sanity check for multiple.
  4.   if (Util.isMultiple(req))
  5.   {
  6.     return false;
  7.   }
  8.   // If we've already permutated this requirement in another
  9.   // uses constraint, don't permutate it again just continue
  10.   // with the next uses constraint.
  11.   if (mutated.contains(req))
  12.   {
  13.     return true;
  14.   }
  15.   // See if we can permutate the candidates for blamed
  16.   // requirement; there may be no candidates if the resource
  17.   // associated with the requirement is already resolved.
  18.   if (permutation.canRemoveCandidate(req))
  19.   {
  20.     permutation.removeFirstCandidate(req);
  21.     mutated.add(req);
  22.     return true;
  23.   }
  24.   return false;
  25. }

代码示例来源：origin: org.eclipse.platform/org.eclipse.osgi

  1. private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
  2. {
  3.   // Sanity check for multiple.
  4.   if (Util.isMultiple(req))
  5.   {
  6.     return false;
  7.   }
  8.   // If we've already permutated this requirement in another
  9.   // uses constraint, don't permutate it again just continue
  10.   // with the next uses constraint.
  11.   if (mutated.contains(req))
  12.   {
  13.     return true;
  14.   }
  15.   // See if we can permutate the candidates for blamed
  16.   // requirement; there may be no candidates if the resource
  17.   // associated with the requirement is already resolved.
  18.   if (permutation.canRemoveCandidate(req))
  19.   {
  20.     permutation.removeFirstCandidate(req);
  21.     mutated.add(req);
  22.     return true;
  23.   }
  24.   return false;
  25. }

代码示例来源：origin: biz.aQute.bnd/biz.aQute.bnd

  1. private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
  2. {
  3.   // Sanity check for multiple.
  4.   if (Util.isMultiple(req))
  5.   {
  6.     return false;
  7.   }
  8.   // If we've already permutated this requirement in another
  9.   // uses constraint, don't permutate it again just continue
  10.   // with the next uses constraint.
  11.   if (mutated.contains(req))
  12.   {
  13.     return true;
  14.   }
  15.   // See if we can permutate the candidates for blamed
  16.   // requirement; there may be no candidates if the resource
  17.   // associated with the requirement is already resolved.
  18.   if (permutation.canRemoveCandidate(req))
  19.   {
  20.     permutation.removeFirstCandidate(req);
  21.     mutated.add(req);
  22.     return true;
  23.   }
  24.   return false;
  25. }

代码示例来源：origin: biz.aQute.bnd/biz.aQute.resolve

  1. private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
  2. {
  3.   // Sanity check for multiple.
  4.   if (Util.isMultiple(req))
  5.   {
  6.     return false;
  7.   }
  8.   // If we've already permutated this requirement in another
  9.   // uses constraint, don't permutate it again just continue
  10.   // with the next uses constraint.
  11.   if (mutated.contains(req))
  12.   {
  13.     return true;
  14.   }
  15.   // See if we can permutate the candidates for blamed
  16.   // requirement; there may be no candidates if the resource
  17.   // associated with the requirement is already resolved.
  18.   if (permutation.canRemoveCandidate(req))
  19.   {
  20.     permutation.removeFirstCandidate(req);
  21.     mutated.add(req);
  22.     return true;
  23.   }
  24.   return false;
  25. }

代码示例来源：origin: com.github.veithen.cosmos/cosmos-equinox

  1. public void permutate(Requirement req, List<Candidates> permutations)
  2. {
  3.   if (!Util.isMultiple(req) && canRemoveCandidate(req))
  4.   {
  5.     Candidates perm = copy();
  6.     perm.removeFirstCandidate(req);
  7.     permutations.add(perm);
  8.   }
  9. }

代码示例来源：origin: org.eclipse.scout.sdk.deps/org.eclipse.osgi

  1. public void permutate(Requirement req, List<Candidates> permutations)
  2. {
  3.   if (!Util.isMultiple(req) && canRemoveCandidate(req))
  4.   {
  5.     Candidates perm = copy();
  6.     perm.removeFirstCandidate(req);
  7.     permutations.add(perm);
  8.   }
  9. }

代码示例来源：origin: org.eclipse.tycho/org.eclipse.osgi

  1. private boolean permuteUsedBlameRequirement(Requirement req, Set<Requirement> mutated, Candidates permutation)
  2. {
  3.   // Sanity check for multiple.
  4.   if (Util.isMultiple(req))
  5.   {
  6.     return false;
  7.   }
  8.   // If we've already permutated this requirement in another
  9.   // uses constraint, don't permutate it again just continue
  10.   // with the next uses constraint.
  11.   if (mutated.contains(req))
  12.   {
  13.     return true;
  14.   }
  15.   // See if we can permutate the candidates for blamed
  16.   // requirement; there may be no candidates if the resource
  17.   // associated with the requirement is already resolved.
  18.   if (permutation.canRemoveCandidate(req))
  19.   {
  20.     permutation.removeFirstCandidate(req);
  21.     mutated.add(req);
  22.     return true;
  23.   }
  24.   return false;
  25. }

代码示例来源：origin: forge/roaster

  1. public Candidates permutate(Requirement req)
  2. {
  3.   if (!Util.isMultiple(req) && canRemoveCandidate(req))
  4.   {
  5.     Candidates perm = copy();
  6.     perm.removeFirstCandidate(req);
  7.     return perm;
  8.   }
  9.   return null;
  10. }

代码示例来源：origin: org.eclipse.tycho/org.eclipse.osgi

  1. public Candidates permutate(Requirement req)
  2. {
  3.   if (!Util.isMultiple(req) && canRemoveCandidate(req))
  4.   {
  5.     Candidates perm = copy();
  6.     perm.removeFirstCandidate(req);
  7.     return perm;
  8.   }
  9.   return null;
  10. }

代码示例来源：origin: apache/felix

  1. public Candidates permutate(Requirement req)
  2. {
  3.   if (!Util.isMultiple(req) && canRemoveCandidate(req))
  4.   {
  5.     Candidates perm = copy();
  6.     perm.removeFirstCandidate(req);
  7.     return perm;
  8.   }
  9.   return null;
  10. }

代码示例来源：origin: biz.aQute.bnd/biz.aQute.bnd

  1. public Candidates permutate(Requirement req)
  2. {
  3.   if (!Util.isMultiple(req) && canRemoveCandidate(req))
  4.   {
  5.     Candidates perm = copy();
  6.     perm.removeFirstCandidate(req);
  7.     return perm;
  8.   }
  9.   return null;
  10. }

代码示例来源：origin: biz.aQute.bnd/biz.aQute.resolve

  1. public Candidates permutate(Requirement req)
  2. {
  3.   if (!Util.isMultiple(req) && canRemoveCandidate(req))
  4.   {
  5.     Candidates perm = copy();
  6.     perm.removeFirstCandidate(req);
  7.     return perm;
  8.   }
  9.   return null;
  10. }

代码示例来源：origin: org.eclipse.platform/org.eclipse.osgi

  1. public Candidates permutate(Requirement req)
  2. {
  3.   if (!Util.isMultiple(req) && canRemoveCandidate(req))
  4.   {
  5.     Candidates perm = copy();
  6.     perm.removeFirstCandidate(req);
  7.     return perm;
  8.   }
  9.   return null;
  10. }

代码示例来源：origin: org.eclipse/osgi

  1. private static void permutate(
  2.   Candidates allCandidates, Requirement req, List<Candidates> permutations)
  3. {
  4.   if (!Util.isMultiple(req))
  5.   {
  6.     List<Capability> candidates = allCandidates.getCandidates(req);
  7.     if ((candidates != null) && (candidates.size() > 1 || Util.isOptional(req)))
  8.     {
  9.       Candidates perm = allCandidates.copy();
  10.       candidates = perm.getCandidates(req);
  11.       candidates.remove(0);
  12.       if (candidates.isEmpty())
  13.       {
  14.         perm.clearCandidates(req);
  15.       }
  16.       permutations.add(perm);
  17.     }
  18.   }
  19. }

代码示例来源：origin: forge/roaster

  1. boolean checkMultiple(
  2.     UsedBlames usedBlames,
  3.     Blame usedBlame,
  4.     Candidates permutation)
  5. {
  6.   // Check the root requirement to see if it is a multiple cardinality
  7.   // requirement.
  8.   CandidateSelector candidates = null;
  9.   Requirement req = usedBlame.m_reqs.get(0);
  10.   if (Util.isMultiple(req))
  11.   {
  12.     // Create a copy of the current permutation so we can remove the
  13.     // candidates causing the blame.
  14.     if (m_multipleCardCandidates == null)
  15.     {
  16.       m_multipleCardCandidates = permutation.copy();
  17.     }
  18.     // Get the current candidate list and remove all the offending root
  19.     // cause candidates from a copy of the current permutation.
  20.     candidates = m_multipleCardCandidates.clearMultipleCardinalityCandidates(req, usedBlames.getRootCauses(req));
  21.   }
  22.   // We only are successful if there is at least one candidate left
  23.   // for the requirement
  24.   return (candidates != null) && !candidates.isEmpty();
  25. }

代码示例来源：origin: org.eclipse.platform/org.eclipse.osgi

  1. boolean checkMultiple(
  2.     UsedBlames usedBlames,
  3.     Blame usedBlame,
  4.     Candidates permutation)
  5. {
  6.   // Check the root requirement to see if it is a multiple cardinality
  7.   // requirement.
  8.   CandidateSelector candidates = null;
  9.   Requirement req = usedBlame.m_reqs.get(0);
  10.   if (Util.isMultiple(req))
  11.   {
  12.     // Create a copy of the current permutation so we can remove the
  13.     // candidates causing the blame.
  14.     if (m_multipleCardCandidates == null)
  15.     {
  16.       m_multipleCardCandidates = permutation.copy();
  17.     }
  18.     // Get the current candidate list and remove all the offending root
  19.     // cause candidates from a copy of the current permutation.
  20.     candidates = m_multipleCardCandidates.clearMultipleCardinalityCandidates(req, usedBlames.getRootCauses(req));
  21.   }
  22.   // We only are successful if there is at least one candidate left
  23.   // for the requirement
  24.   return (candidates != null) && !candidates.isEmpty();
  25. }

代码示例来源：origin: biz.aQute.bnd/biz.aQute.resolve

  1. boolean checkMultiple(
  2.     UsedBlames usedBlames,
  3.     Blame usedBlame,
  4.     Candidates permutation)
  5. {
  6.   // Check the root requirement to see if it is a multiple cardinality
  7.   // requirement.
  8.   CandidateSelector candidates = null;
  9.   Requirement req = usedBlame.m_reqs.get(0);
  10.   if (Util.isMultiple(req))
  11.   {
  12.     // Create a copy of the current permutation so we can remove the
  13.     // candidates causing the blame.
  14.     if (m_multipleCardCandidates == null)
  15.     {
  16.       m_multipleCardCandidates = permutation.copy();
  17.     }
  18.     // Get the current candidate list and remove all the offending root
  19.     // cause candidates from a copy of the current permutation.
  20.     candidates = m_multipleCardCandidates.clearMultipleCardinalityCandidates(req, usedBlames.getRootCauses(req));
  21.   }
  22.   // We only are successful if there is at least one candidate left
  23.   // for the requirement
  24.   return (candidates != null) && !candidates.isEmpty();
  25. }

代码示例来源：origin: org.eclipse.scout.sdk.deps/org.eclipse.osgi

  1. private boolean checkMultiple(
  2.   ResolveSession session,
  3.   UsedBlames usedBlames,
  4.   Blame usedBlame,
  5.   Candidates permutation)
  6. {
  7.   // Check the root requirement to see if it is a multiple cardinality
  8.   // requirement.
  9.   List<Capability> candidates = null;
  10.   Requirement req = usedBlame.m_reqs.get(0);
  11.   if (Util.isMultiple(req))
  12.   {
  13.     // Create a copy of the current permutation so we can remove the
  14.     // candidates causing the blame.
  15.     if (session.getMultipleCardCandidates() == null)
  16.     {
  17.       session.setMultipleCardCandidates(permutation.copy());
  18.     }
  19.     // Get the current candidate list and remove all the offending root
  20.     // cause candidates from a copy of the current permutation.
  21.     candidates = session.getMultipleCardCandidates().clearCandidates(req, usedBlames.getRootCauses(req));
  22.   }
  23.   // We only are successful if there is at least one candidate left
  24.   // for the requirement
  25.   return (candidates != null) && !candidates.isEmpty();
  26. }

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