本文整理了Java中org.apache.xalan.processor.XSLTElementDef.isOrdered()方法的一些代码示例，展示了XSLTElementDef.isOrdered()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。XSLTElementDef.isOrdered()方法的具体详情如下：
包路径：org.apache.xalan.processor.XSLTElementDef
类名称：XSLTElementDef
方法名：isOrdered

XSLTElementDef.isOrdered介绍

[英]Get whether this element requires ordered children.
[中]获取此元素是否需要有序的子元素。

代码示例

代码示例来源：origin: robovm/robovm

if (elemDef != null && this.isOrdered())

代码示例来源：origin: xalan/xalan

if (elemDef != null && this.isOrdered())

代码示例来源：origin: ibinti/bugvm

if (elemDef != null && this.isOrdered())

代码示例来源：origin: FlexoVM/flexovm

if (elemDef != null && this.isOrdered())

代码示例来源：origin: MobiVM/robovm

if (elemDef != null && this.isOrdered())

代码示例来源：origin: com.mobidevelop.robovm/robovm-rt

if (elemDef != null && this.isOrdered())

代码示例来源：origin: org.apache.servicemix.bundles/org.apache.servicemix.bundles.xalan

if (elemDef != null && this.isOrdered())

代码示例来源：origin: com.gluonhq/robovm-rt

if (elemDef != null && this.isOrdered())

代码示例来源：origin: org.apache.xalan/com.springsource.org.apache.xalan

if (elemDef != null && this.isOrdered())

代码示例来源：origin: com.bugvm/bugvm-rt

if (elemDef != null && this.isOrdered())

代码示例来源：origin: org.apache.karaf.bundles/org.apache.karaf.bundles.xalan-2.7.1

if (elemDef != null && this.isOrdered())