本文整理了Java中org.json.simple.parser.Yylex.yylex()方法的一些代码示例，展示了Yylex.yylex()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Yylex.yylex()方法的具体详情如下：
包路径：org.json.simple.parser.Yylex
类名称：Yylex
方法名：yylex

Yylex.yylex介绍

[英]Resumes scanning until the next regular expression is matched, the end of input is encountered or an I/O-Error occurs.
[中]继续扫描，直到下一个正则表达式匹配、遇到输入结束或发生I/O错误。

代码示例

代码示例来源：origin: com.googlecode.json-simple/json-simple

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源：origin: i2p/i2p.i2p

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源：origin: fangyidong/json-simple

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源：origin: childe/hangout

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源：origin: pstehlik/gelf4j

private void nextToken() throws ParseException, IOException{
  token = lexer.yylex();
  if(token == null)
    token = new Yytoken(Yytoken.TYPE_EOF, null);
}

代码示例来源：origin: stackoverflow.com

while ((t = yy.yylex()) != null) {
 String text = t.mText;

代码示例来源：origin: BiglySoftware/BiglyBT

token=lexer.yylex();
if(token==null)
  token=new Yytoken(Yytoken.TYPE_EOF,null);