java.lang.Math.IEEEremainder()方法的使用及代码示例

x33g5p2x  于2022-01-16 转载在 其他  
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本文整理了Java中java.lang.Math.IEEEremainder()方法的一些代码示例，展示了Math.IEEEremainder()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Math.IEEEremainder()方法的具体详情如下：
包路径：java.lang.Math
类名称：Math
方法名：IEEEremainder

Math.IEEEremainder介绍

[英]Returns the remainder of dividing x by y using the IEEE 754 rules. The result is x-round(x/p)*p where round(x/p)is the nearest integer (rounded to even), but without numerical cancellation problems.

Special cases:

  • IEEEremainder((anything), 0) = NaN
  • IEEEremainder(+infinity, (anything)) = NaN
  • IEEEremainder(-infinity, (anything)) = NaN
  • IEEEremainder(NaN, (anything)) = NaN
  • IEEEremainder((anything), NaN) = NaN
  • IEEEremainder(x, +infinity) = x where x is anything but +/-infinity
  • IEEEremainder(x, -infinity) = x where x is anything but +/-infinity
    [中]

代码示例

代码示例来源：origin: apache/mahout

  1. @Override
  2.  public double apply(double a, double b) {
  3.   return Math.IEEEremainder(a, b);
  4.  }
  5. };

代码示例来源：origin: apache/mahout

  1. @Override
  2.  public double apply(double a) {
  3.   return Math.IEEEremainder(a, b);
  4.  }
  5. };

代码示例来源：origin: apache/incubator-druid

  1. @Override
  2.  protected ExprEval eval(double x, double y)
  3.  {
  4.   return ExprEval.of(Math.IEEEremainder(x, y));
  5.  }
  6. }

代码示例来源：origin: geotools/geotools

  1. public Object evaluate(Object feature) {
  2.     double arg0;
  3.     double arg1;
  5.     try { // attempt to get value and perform conversion
  6.       arg0 = getExpression(0).evaluate(feature, Double.class).doubleValue();
  7.     } catch (Exception e) {
  8.       // probably a type error
  9.       throw new IllegalArgumentException(
  10.           "Filter Function problem for function IEEEremainder argument #0 - expected type double");
  11.     }
  13.     try { // attempt to get value and perform conversion
  14.       arg1 = getExpression(1).evaluate(feature, Double.class).doubleValue();
  15.     } catch (Exception e) {
  16.       // probably a type error
  17.       throw new IllegalArgumentException(
  18.           "Filter Function problem for function IEEEremainder argument #1 - expected type double");
  19.     }
  21.     return new Double(Math.IEEEremainder(arg0, arg1));
  22.   }
  23. }

代码示例来源：origin: edu.ucar/netcdf

  1. /**
  2.  * put longitude into the range [center +/- 180] deg
  3.  *
  4.  * @param lon    lon to normalize
  5.  * @param center center point
  6.  * @return longitude into the range [center +/- 180] deg
  7.  */
  8. static public double lonNormal(double lon, double center) {
  9.  return center + Math.IEEEremainder(lon - center, 360.0);
  10. }

代码示例来源：origin: org.carrot2/carrot2-core

  1. @Override
  2.  public double apply(double a, double b) {
  3.   return Math.IEEEremainder(a, b);
  4.  }
  5. };

代码示例来源：origin: dhale/jtk

  1. /**
  2.  * Computes the remainder operation on two arguments as prescribed by the 
  3.  * IEEE 754 standard.
  4.  * @param f1 the dividend.
  5.  * @param f2 the divisor.
  6.  * @return the remainder when f1 is divided by f2
  7.  */
  8. public static float IEEEremainder(float f1, float f2) {
  9.  return (float)Math.IEEEremainder(f1,f2);
  10. }

代码示例来源：origin: Unidata/thredds

  1. /**
  2.  * Find difference (lon1 - lon2) normalized so that maximum value is += 180.
  3.  * @param lon1 start
  4.  * @param lon2 end
  5.  * @return
  6.  */
  7. static public double lonDiff(double lon1, double lon2) {
  8.  return Math.IEEEremainder(lon1-lon2, 360.0);
  9. }

代码示例来源：origin: lenskit/lenskit

  1. @Test
  2.   public void testStorableDoubles() {
  3.     for (double d: toIterable(doubles(), 10000)) {
  4.       assertThat(DoubleShard.Compact.isStorable(d),
  5.             equalTo(d > -64 && d < 64 && Scalars.isZero(Math.IEEEremainder(d, 0.5))));
  6.     }
  7.   }
  8. }

代码示例来源：origin: edu.ucar/cdm

  1. /**
  2.  * put longitude into the range [center +/- 180] deg
  3.  *
  4.  * @param lon    lon to normalize
  5.  * @param center center point
  6.  * @return longitude into the range [center +/- 180] deg
  7.  */
  8. static public double lonNormal(double lon, double center) {
  9.  return center + Math.IEEEremainder(lon - center, 360.0);
  10. }

代码示例来源：origin: org.apache.mahout/mahout-math

  1. @Override
  2.  public double apply(double a) {
  3.   return Math.IEEEremainder(a, b);
  4.  }
  5. };

代码示例来源：origin: com.github.haifengl/smile-math

  1. /**
  2.  * Computes the remainder operation on two arguments as prescribed by the IEEE 754 standard.
  3.  */
  4. public static double IEEEremainder(double f1, double f2) {
  5.   return java.lang.Math.IEEEremainder(f1, f2);
  6. }

代码示例来源：origin: edu.ucar/unidataCommon

  1. /**
  2.  * put longitude into the range [center +/- 180] deg
  3.  *
  4.  * @param lon    lon to normalize
  5.  * @param center center point
  6.  * @return longitude into the range [center +/- 180] deg
  7.  */
  8. static public double lonNormal(double lon, double center) {
  9.  return center + Math.IEEEremainder(lon - center, 360.0);
  10. }

代码示例来源：origin: org.carrot2/carrot2-core

  1. @Override
  2.  public double apply(double a) {
  3.   return Math.IEEEremainder(a, b);
  4.  }
  5. };

代码示例来源：origin: geotools/geotools

  1. double good0 = Math.IEEEremainder(1.0, -1.0);
  2. if (Double.isNaN(good0)) {
  3.   assertTrue(
  4.   assertEquals(
  5.       "IEEEremainder of (1.0,-1.0):",
  6.       (double) Math.IEEEremainder(1.0, -1.0),
  7.       ((Double) IEEEremainderFunction.evaluate(null)).doubleValue(),
  8.       0.00001);
  9. double good1 = Math.IEEEremainder(-1.0, 2.0);
  10. if (Double.isNaN(good1)) {
  11.   assertTrue(
  12.   assertEquals(
  13.       "IEEEremainder of (-1.0,2.0):",
  14.       (double) Math.IEEEremainder(-1.0, 2.0),
  15.       ((Double) IEEEremainderFunction.evaluate(null)).doubleValue(),
  16.       0.00001);
  17. double good2 = Math.IEEEremainder(2.0, -2.0);
  18. if (Double.isNaN(good2)) {
  19.   assertTrue(
  20.   assertEquals(
  21.       "IEEEremainder of (2.0,-2.0):",
  22.       (double) Math.IEEEremainder(2.0, -2.0),
  23.       ((Double) IEEEremainderFunction.evaluate(null)).doubleValue(),
  24.       0.00001);

代码示例来源：origin: org.jruby/jruby-complete

  1. public IRubyObject op_mod(ThreadContext context, double other) {
  2.   // Modelled after c ruby implementation (java /,% not same as ruby)
  3.   double x = value;
  4.   double mod = Math.IEEEremainder(x, other);
  5.   if (other * mod < 0) {
  6.     mod += other;
  7.   }
  8.   return RubyFloat.newFloat(context.runtime, mod);
  9. }

代码示例来源：origin: Esri/geometry-api-java

  1. static private double lam_delta(double lam) {
  2.   double d = Math.IEEEremainder(lam, PE_2PI);
  3.   return (PE_ABS(d) <= PE_PI) ? d : ((d < 0) ? d + PE_2PI : d - PE_2PI);
  4. }

代码示例来源：origin: Unidata/thredds

  1. /**
  2.   * Starting from lon1, find
  3.   * Find difference (lon1 - lon2) normalized so that maximum value is += 180.
  4.   *
  5.   * @param lon1 start
  6.   * @param lon2 end
  7.   * @return
  8.   */
  9.  static public double lonDiff(double lon1, double lon2) {
  10.   return Math.IEEEremainder(lon1 - lon2, 720.0);
  11.  }
  12. }

代码示例来源：origin: com.ning.billing/killbill-osgi-bundles-jruby

  1. public IRubyObject op_mod(ThreadContext context, double other) {
  2.   // Modelled after c ruby implementation (java /,% not same as ruby)
  3.   double x = value;
  4.   double mod = Math.IEEEremainder(x, other);
  5.   if (other * mod < 0) {
  6.     mod += other;
  7.   }
  8.   return RubyFloat.newFloat(getRuntime(), mod);
  9. }

代码示例来源：origin: org.kill-bill.billing/killbill-osgi-bundles-jruby

  1. public IRubyObject op_mod(ThreadContext context, double other) {
  2.   // Modelled after c ruby implementation (java /,% not same as ruby)
  3.   double x = value;
  4.   double mod = Math.IEEEremainder(x, other);
  5.   if (other * mod < 0) {
  6.     mod += other;
  7.   }
  8.   return RubyFloat.newFloat(getRuntime(), mod);
  9. }

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