org.vertx.java.core.buffer.Buffer.getString()方法的使用及代码示例

x33g5p2x  于2022-01-16 转载在 其他  
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本文整理了Java中org.vertx.java.core.buffer.Buffer.getString()方法的一些代码示例,展示了Buffer.getString()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Buffer.getString()方法的具体详情如下:
包路径:org.vertx.java.core.buffer.Buffer
类名称:Buffer
方法名:getString

Buffer.getString介绍

[英]Returns a copy of a sub-sequence the Buffer as a String starting at position startand ending at position end - 1 interpreted as a String in UTF-8 encoding
[中]将缓冲区中的子序列的副本作为字符串返回,该字符串从位置START开始,在位置end-1结束,在UTF-8编码中被解释为字符串

代码示例

代码示例来源:origin: io.fabric8/gateway-core

public String contentAsString() {
  return content.getString(0, content.length(), "UTF-8");
}

代码示例来源:origin: jboss-fuse/fabric8

public String contentAsString() {
  return content.getString(0, content.length(), "UTF-8");
}

代码示例来源:origin: vert-x/mod-lang-php

public Value getString(Env env, NumberValue start, NumberValue end) {
 return env.wrapJava(buffer.getString(start.toInt(), end.toInt()));
}

代码示例来源:origin: io.fabric8/gateway-apiman

@Override
public void handle(Buffer event) {
  try {
    String body = event.getString(0, event.length());
    String uri = request.uri().substring(1);
    if (uri.contains("?")) uri = uri.substring(0, uri.indexOf("?"));

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