com.microsoft.azure.management.Azure.deployments()方法的使用及代码示例

x33g5p2x  于2022-01-17 转载在 其他  
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本文整理了Java中com.microsoft.azure.management.Azure.deployments()方法的一些代码示例,展示了Azure.deployments()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Azure.deployments()方法的具体详情如下:
包路径:com.microsoft.azure.management.Azure
类名称:Azure
方法名:deployments

Azure.deployments介绍

暂无

代码示例

代码示例来源:origin: jenkinsci/azure-vm-agents-plugin

  1. deployment = azureClient.deployments().
  2. getByResourceGroup(info.getResourceGroupName(), info.getDeploymentName());
  3. } catch (NullPointerException e) {
  4. failTimeoutInMinutes);
  5. azureClient.deployments()
  6. .deleteByResourceGroup(info.getResourceGroupName(), info.getDeploymentName());
  7. if (StringUtils.isNotBlank(info.scriptUri)) {
  8. successTimeoutInMinutes);
  9. azureClient.deployments()
  10. .deleteByResourceGroup(info.getResourceGroupName(), info.getDeploymentName());
  11. if (StringUtils.isNotBlank(info.scriptUri)) {

代码示例来源:origin: jenkinsci/azure-vm-agents-plugin

  1. final Deployment dep = newAzureClient.deployments().getByName(deploymentName);

代码示例来源:origin: jenkinsci/azure-vm-agents-plugin

  1. template.getAzureCloud().getCloudName(), template.getResourceGroupName(), deploymentName, scriptUri);
  2. azureClient.deployments().define(deploymentName)
  3. .withExistingResourceGroup(template.getResourceGroupName())
  4. .withTemplate(tmp.toString())

代码示例来源:origin: gradle.plugin.com.intershop.gradle.plugin.azure/azurePlugin

  1. deployment = getClient().deployments()
  2. .define(deploymentId.get())
  3. .withExistingResourceGroup(resourceGroup.get().name())
  4. deployment = getClient().deployments()
  5. .define(deploymentId.get())
  6. .withExistingResourceGroup(resourceGroup.get().name())

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