本文整理了Java中org.apache.lucene.util.automaton.Operations.subsetOf()方法的一些代码示例，展示了Operations.subsetOf()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Operations.subsetOf()方法的具体详情如下：
包路径：org.apache.lucene.util.automaton.Operations
类名称：Operations
方法名：subsetOf

Operations.subsetOf介绍

[英]Returns true if the language of a1 is a subset of the language of a2. Both automata must be determinized and must have no dead states.

Complexity: quadratic in number of states.
[中]如果a1的语言是[$1$]语言的子集，则返回true。这两个自动机都必须是确定的，并且必须没有死态。
复杂性：状态数为二次。

代码示例

代码示例来源：origin: org.apache.lucene/lucene-core

/** Returns true if these two automata accept exactly the
 *  same language.  This is a costly computation!  Both automata
 *  must be determinized and have no dead states! */
public static boolean sameLanguage(Automaton a1, Automaton a2) {
 if (a1 == a2) {
  return true;
 }
 return subsetOf(a2, a1) && subsetOf(a1, a2);
}

代码示例来源：origin: org.apache.servicemix.bundles/org.apache.servicemix.bundles.lucene

/** Returns true if these two automata accept exactly the
 *  same language.  This is a costly computation!  Both automata
 *  must be determinized and have no dead states! */
public static boolean sameLanguage(Automaton a1, Automaton a2) {
 if (a1 == a2) {
  return true;
 }
 return subsetOf(a2, a1) && subsetOf(a1, a2);
}

代码示例来源：origin: harbby/presto-connectors

/** Returns true if these two automata accept exactly the
 *  same language.  This is a costly computation!  Note
 *  also that a1 and a2 will be determinized as a side
 *  effect.  Both automata must be determinized and have
 *  no dead states! */
public static boolean sameLanguage(Automaton a1, Automaton a2) {
 if (a1 == a2) {
  return true;
 }
 return subsetOf(a2, a1) && subsetOf(a1, a2);
}

代码示例来源：origin: org.infinispan/infinispan-embedded-query

/** Returns true if these two automata accept exactly the
 *  same language.  This is a costly computation!  Note
 *  also that a1 and a2 will be determinized as a side
 *  effect.  Both automata must be determinized and have
 *  no dead states! */
public static boolean sameLanguage(Automaton a1, Automaton a2) {
 if (a1 == a2) {
  return true;
 }
 return subsetOf(a2, a1) && subsetOf(a1, a2);
}