org.apache.lucene.util.automaton.Operations.hasDeadStatesFromInitial()方法的使用及代码示例

x33g5p2x  于2022-01-26 转载在 其他  
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本文整理了Java中org.apache.lucene.util.automaton.Operations.hasDeadStatesFromInitial()方法的一些代码示例,展示了Operations.hasDeadStatesFromInitial()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Operations.hasDeadStatesFromInitial()方法的具体详情如下:
包路径:org.apache.lucene.util.automaton.Operations
类名称:Operations
方法名:hasDeadStatesFromInitial

Operations.hasDeadStatesFromInitial介绍

[英]Returns true if there are dead states reachable from an initial state.
[中]如果存在可从初始状态访问的死状态,则返回true。

代码示例

代码示例来源:origin: org.apache.lucene/lucene-core

  1. throw new IllegalArgumentException("a2 must be deterministic");
  2. assert hasDeadStatesFromInitial(a1) == false;
  3. assert hasDeadStatesFromInitial(a2) == false;
  4. if (a1.getNumStates() == 0) {

代码示例来源:origin: harbby/presto-connectors

  1. throw new IllegalArgumentException("a2 must be deterministic");
  2. assert hasDeadStatesFromInitial(a1) == false;
  3. assert hasDeadStatesFromInitial(a2) == false;
  4. if (a1.getNumStates() == 0) {

代码示例来源:origin: org.infinispan/infinispan-embedded-query

  1. throw new IllegalArgumentException("a2 must be deterministic");
  2. assert hasDeadStatesFromInitial(a1) == false;
  3. assert hasDeadStatesFromInitial(a2) == false;
  4. if (a1.getNumStates() == 0) {

代码示例来源:origin: org.apache.servicemix.bundles/org.apache.servicemix.bundles.lucene

  1. throw new IllegalArgumentException("a2 must be deterministic");
  2. assert hasDeadStatesFromInitial(a1) == false;
  3. assert hasDeadStatesFromInitial(a2) == false;
  4. if (a1.getNumStates() == 0) {

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