org.nd4j.linalg.factory.Nd4j.clearNans()方法的使用及代码示例

x33g5p2x  于2022-01-24 转载在 其他  
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本文整理了Java中org.nd4j.linalg.factory.Nd4j.clearNans()方法的一些代码示例，展示了Nd4j.clearNans()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Nd4j.clearNans()方法的具体详情如下：
包路径：org.nd4j.linalg.factory.Nd4j
类名称：Nd4j
方法名：clearNans

Nd4j.clearNans介绍

[英]Clear nans from an ndarray
[中]把南斯从黑暗中清除出去

代码示例

代码示例来源：origin: deeplearning4j/nd4j

  1. @Override
  2. public INDArray rsubi(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarReverseSubtraction(this, null, result, result.lengthLong(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: deeplearning4j/nd4j

  1. @Override
  2. public INDArray rdivi(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarReverseDivision(this, null, result, result.length(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: deeplearning4j/nd4j

  1. @Override
  2. public INDArray divi(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarDivision(this, null, result, result.lengthLong(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: deeplearning4j/nd4j

  1. @Override
  2. public INDArray muli(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarMultiplication(this, null, result, result.lengthLong(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: deeplearning4j/nd4j

  1. @Override
  2. public INDArray subi(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarSubtraction(this, null, result, result.lengthLong(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: deeplearning4j/nd4j

  1. /**
  2.  * in place subtraction of two matrices
  3.  *
  4.  * @param other  the second ndarray to subtract
  5.  * @param result the result ndarray
  6.  * @return the result of the subtraction
  7.  */
  8. @Override
  9. public INDArray subi(INDArray other, INDArray result) {
  10.   if (other.isScalar()) {
  11.     return subi(other.getDouble(0), result);
  12.   }
  13.   if (isScalar()) {
  14.     return other.rsubi(getDouble(0), result);
  15.   }
  16.   if(!Shape.shapeEquals(this.shape(),other.shape())) {
  17.     int[] broadcastDimensions = Shape.getBroadcastDimensions(this.shape(),other.shape());
  18.     Nd4j.getExecutioner().exec(new BroadcastSubOp(this,other,result,broadcastDimensions),broadcastDimensions);
  19.     return result;
  20.   }
  21.   LinAlgExceptions.assertSameShape(other, result);
  22.   Nd4j.getExecutioner().exec(new OldSubOp(this, other,result));
  23.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  24.     Nd4j.clearNans(result);
  25.   return result;
  26. }

代码示例来源：origin: deeplearning4j/nd4j

  1. /**
  2.  * in place (element wise) multiplication of two matrices
  3.  *
  4.  * @param other  the second ndarray to multiply
  5.  * @param result the result ndarray
  6.  * @return the result of the multiplication
  7.  */
  8. @Override
  9. public INDArray muli(INDArray other, INDArray result) {
  10.   if (other.isScalar()) {
  11.     return muli(other.getDouble(0), result);
  12.   }
  13.   if (isScalar()) {
  14.     return other.muli(getDouble(0), result);
  15.   }
  16.   if(!Shape.shapeEquals(this.shape(),other.shape())) {
  17.     int[] broadcastDimensions = Shape.getBroadcastDimensions(this.shape(),other.shape());
  18.     Nd4j.getExecutioner().exec(new BroadcastMulOp(this,other,result,broadcastDimensions),broadcastDimensions);
  19.     return result;
  20.   }
  21.   LinAlgExceptions.assertSameShape(other, result);
  22.   Nd4j.getExecutioner().exec(new OldMulOp(this, other, result, length()));
  23.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  24.     Nd4j.clearNans(result);
  25.   return result;
  26. }

代码示例来源：origin: deeplearning4j/nd4j

  1. /**
  2.  * in place (element wise) division of two matrices
  3.  *
  4.  * @param other  the second ndarray to divide
  5.  * @param result the result ndarray
  6.  * @return the result of the divide
  7.  */
  8. @Override
  9. public INDArray divi(INDArray other, INDArray result) {
  10.   if (other.isScalar()) {
  11.     return divi(other.getDouble(0), result);
  12.   }
  13.   if (isScalar()) {
  14.     return other.rdivi(getDouble(0), result);
  15.   }
  16.   if(!Shape.shapeEquals(this.shape(),other.shape())) {
  17.     int[] broadcastDimensions = Shape.getBroadcastDimensions(this.shape(),other.shape());
  18.     Nd4j.getExecutioner().exec(new BroadcastDivOp(this,other,result,broadcastDimensions),broadcastDimensions);
  19.     return result;
  20.   }
  21.   LinAlgExceptions.assertSameShape(other, result);
  22.   Nd4j.getExecutioner().exec(new OldDivOp(this, other, result, length()));
  23.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  24.     Nd4j.clearNans(result);
  25.   return result;
  26. }

代码示例来源：origin: deeplearning4j/nd4j

  1. /**
  2.  * in place addition of two matrices
  3.  *
  4.  * @param other  the second ndarray to add
  5.  * @param result the result ndarray
  6.  * @return the result of the addition
  7.  */
  8. @Override
  9. public INDArray addi(INDArray other, INDArray result) {
  10.   if (other.isScalar()) {
  11.     return result.addi(other.getDouble(0), result);
  12.   }
  13.   if (isScalar()) {
  14.     return other.addi(getDouble(0), result);
  15.   }
  16.   if(!Shape.shapeEquals(this.shape(),other.shape())) {
  17.     int[] broadcastDimensions = Shape.getBroadcastDimensions(this.shape(),other.shape());
  18.     result = Nd4j.createUninitialized(Shape.broadcastOutputShape(this.shape(),other.shape()));
  19.     Nd4j.getExecutioner().exec(new BroadcastAddOp(this,other,result,broadcastDimensions),broadcastDimensions);
  20.     return result;
  21.   }
  22.   LinAlgExceptions.assertSameShape(other, result);
  23.   Nd4j.getExecutioner().exec(new OldAddOp(this, other, result, length()));
  24.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  25.     Nd4j.clearNans(result);
  26.   return result;
  27. }

代码示例来源：origin: deeplearning4j/nd4j

  1. Nd4j.clearNans(result);

代码示例来源：origin: deeplearning4j/nd4j

  1. Nd4j.clearNans(result);
  2. return result;

代码示例来源：origin: org.nd4j/nd4j-api

  1. @Override
  2. public INDArray rsubi(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarReverseSubtraction(this, null, result, result.lengthLong(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: org.nd4j/nd4j-api

  1. @Override
  2. public INDArray divi(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarDivision(this, null, result, result.lengthLong(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: org.nd4j/nd4j-api

  1. @Override
  2. public INDArray subi(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarSubtraction(this, null, result, result.lengthLong(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: org.nd4j/nd4j-api

  1. @Override
  2. public INDArray rdivi(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarReverseDivision(this, null, result, result.length(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: org.nd4j/nd4j-api

  1. @Override
  2. public INDArray muli(Number n, INDArray result) {
  3.   if (Double.isNaN(n.doubleValue()))
  4.     n = Nd4j.EPS_THRESHOLD;
  5.   Nd4j.getExecutioner().exec(new ScalarMultiplication(this, null, result, result.lengthLong(), n));
  6.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  7.     Nd4j.clearNans(result);
  8.   return result;
  9. }

代码示例来源：origin: neo4j-graph-analytics/ml-models

  1. @Override
  2. public INDArray ndOp(INDArray features, INDArray adjacencyMatrix) {
  3.   INDArray mean = adjacencyMatrix
  4.       .mmul(features)
  5.       .diviColumnVector(adjacencyMatrix.sum(1));
  6.   // clear NaNs from div by 0 - these entries should have a 0 instead.
  7.   Nd4j.clearNans(mean);
  8.   return mean;
  9. }

代码示例来源：origin: org.nd4j/nd4j-api

  1. /**
  2.  * in place addition of two matrices
  3.  *
  4.  * @param other  the second ndarray to add
  5.  * @param result the result ndarray
  6.  * @return the result of the addition
  7.  */
  8. @Override
  9. public INDArray addi(INDArray other, INDArray result) {
  10.   if (other.isScalar()) {
  11.     return result.addi(other.getDouble(0), result);
  12.   }
  13.   if (isScalar()) {
  14.     return other.addi(getDouble(0), result);
  15.   }
  16.   LinAlgExceptions.assertSameShape(other, result);
  17.   Nd4j.getExecutioner().exec(new AddOp(this, other, result));
  18.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  19.     Nd4j.clearNans(result);
  20.   return result;
  21. }

代码示例来源：origin: org.nd4j/nd4j-api

  1. /**
  2.  * in place subtraction of two matrices
  3.  *
  4.  * @param other  the second ndarray to subtract
  5.  * @param result the result ndarray
  6.  * @return the result of the subtraction
  7.  */
  8. @Override
  9. public INDArray subi(INDArray other, INDArray result) {
  10.   if (other.isScalar()) {
  11.     return subi(other.getDouble(0), result);
  12.   }
  13.   if (isScalar()) {
  14.     return other.subi(getDouble(0), result);
  15.   }
  16.   LinAlgExceptions.assertSameShape(other, result);
  17.   Nd4j.getExecutioner().exec(new SubOp(this, other, result, length()));
  18.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  19.     Nd4j.clearNans(result);
  20.   return result;
  21. }

代码示例来源：origin: org.nd4j/nd4j-api

  1. /**
  2.  * in place (element wise) division of two matrices
  3.  *
  4.  * @param other  the second ndarray to divide
  5.  * @param result the result ndarray
  6.  * @return the result of the divide
  7.  */
  8. @Override
  9. public INDArray divi(INDArray other, INDArray result) {
  10.   if (other.isScalar()) {
  11.     return divi(other.getDouble(0), result);
  12.   }
  13.   if (isScalar()) {
  14.     return other.divi(getDouble(0), result);
  15.   }
  16.   LinAlgExceptions.assertSameShape(other, result);
  17.   Nd4j.getExecutioner().exec(new DivOp(this, other, result, length()));
  18.   if (Nd4j.ENFORCE_NUMERICAL_STABILITY)
  19.     Nd4j.clearNans(result);
  20.   return result;
  21. }

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