本文整理了Java中com.ardor3d.scenegraph.Node.detachChildAt()方法的一些代码示例，展示了Node.detachChildAt()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Node.detachChildAt()方法的具体详情如下：
包路径：com.ardor3d.scenegraph.Node
类名称：Node
方法名：detachChildAt

Node.detachChildAt介绍

[英]detachChildAt removes a child at a given index. That child is returned for saving purposes.
[中]detachChildAt删除给定索引处的子项。那孩子是为了省钱才被送回的。

代码示例

代码示例来源：origin: com.ardor3d/ardor3d-core

@Override
public Spatial detachChildAt(final int index) {
  return _targetScene.detachChildAt(index);
}

代码示例来源：origin: Renanse/Ardor3D

@Override
public Spatial detachChildAt(final int index) {
  return _targetScene.detachChildAt(index);
}

代码示例来源：origin: Renanse/Ardor3D

/**
 *
 * <code>detachAllChildren</code> removes all children attached to this node.
 */
public void detachAllChildren() {
  for (int i = getNumberOfChildren() - 1; i >= 0; i--) {
    detachChildAt(i);
  }
  logger.fine("All children removed.");
}

代码示例来源：origin: com.ardor3d/ardor3d-core

/**
 * 
 * <code>detachAllChildren</code> removes all children attached to this node.
 */
public void detachAllChildren() {
  for (int i = getNumberOfChildren() - 1; i >= 0; i--) {
    detachChildAt(i);
  }
  logger.fine("All children removed.");
}

代码示例来源：origin: com.ardor3d/ardor3d-core

/**
 * <code>detachChild</code> removes a given child from the node's list. This child will no longe be maintained.
 * 
 * @param child
 *            the child to remove.
 * @return the index the child was at. -1 if the child was not in the list.
 */
public int detachChild(final Spatial child) {
  if (child == null) {
    return -1;
  }
  if (child.getParent() == this) {
    final int index = _children.indexOf(child);
    if (index != -1) {
      detachChildAt(index);
    }
    return index;
  }
  return -1;
}

代码示例来源：origin: Renanse/Ardor3D

/**
 * <code>detachChild</code> removes a given child from the node's list. This child will no longe be maintained.
 *
 * @param child
 *            the child to remove.
 * @return the index the child was at. -1 if the child was not in the list.
 */
public int detachChild(final Spatial child) {
  if (child == null) {
    return -1;
  }
  if (child.getParent() == this) {
    final int index = _children.indexOf(child);
    if (index != -1) {
      detachChildAt(index);
    }
    return index;
  }
  return -1;
}

代码示例来源：origin: com.ardor3d/ardor3d-core

/**
 * <code>detachChild</code> removes a given child from the node's list. This child will no longe be maintained. Only
 * the first child with a matching name is removed.
 * 
 * @param childName
 *            the child to remove.
 * @return the index the child was at. -1 if the child was not in the list.
 */
public int detachChildNamed(final String childName) {
  if (childName == null) {
    return -1;
  }
  for (int i = getNumberOfChildren() - 1; i >= 0; i--) {
    final Spatial child = _children.get(i);
    if (childName.equals(child.getName())) {
      detachChildAt(i);
      return i;
    }
  }
  return -1;
}

代码示例来源：origin: Renanse/Ardor3D

/**
 * <code>detachChild</code> removes a given child from the node's list. This child will no longe be maintained. Only
 * the first child with a matching name is removed.
 *
 * @param childName
 *            the child to remove.
 * @return the index the child was at. -1 if the child was not in the list.
 */
public int detachChildNamed(final String childName) {
  if (childName == null) {
    return -1;
  }
  for (int i = getNumberOfChildren() - 1; i >= 0; i--) {
    final Spatial child = _children.get(i);
    if (childName.equals(child.getName())) {
      detachChildAt(i);
      return i;
    }
  }
  return -1;
}